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nikklg [1K]
3 years ago
5

Which matrix multiplication is defined ?

Mathematics
1 answer:
eimsori [14]3 years ago
7 0

Answer:

A. CB

Step-by-step explanation:

3 x 2 (C is a 3 by 2) matrix can be multiplied to a 2 x 2 (B is a 2 by 2) matrix since C has 2 columns that are equal to the number of rows in the second matrix B.

A way of checking if two matrices can be multiplied is to first check the number of columns the first matrix contains and then check the number of rows that the second matrix contains.

If the number of columns in the first matrix equal the number of rows in the second matrix then that means it is possible to multiply these matrices.

You might be interested in
What two numbers multiply to -112 and add up to -54
SVETLANKA909090 [29]
Xy = -112
x + y = -54

xy = -112
\frac{xy}{x} = \frac{-112}{x}
y = \frac{-112}{x}

x + y = -54
x + \frac{-112}{x} = -54
\frac{x^{2}}{x} + \frac{-112}{x} = -54
\frac{x^{2} - 112}{x} = -54
x^{2} - 112 = -54x
x^{2} + 54x - 112 = 0
x^{2} + 56x - 2x - 112 = 0
x(x) + x(56) - 2(x) - 2(56) = 0
x(x + 56) - 2(x + 56) = 0
(x - 2)(x + 56) = 0
x - 2 = 0    or    x + 56 = 0
x = 2    or    x = -56

  x + y = -54
  2 + y = -54
- 2           - 2
        y = -56
  (x, y) = (2, -56)

          or

     x + y = -54
  -56 + y = -54
+ 56        + 56
           y = 2
    (x, y) = (-56, 2)

The two numbers that multiply to -12 and add up to -54 are -56 and 2.
6 0
4 years ago
Read 2 more answers
What is the solution to the system of equations
Arada [10]

Answer:

(3,-2)

Step-by-step explanation:

Got it right!!

6 0
3 years ago
Read 2 more answers
Solve the system of linear equations by elimination.<br><br> 4x+3y=−5<br> −x+3y=−10
Mrrafil [7]
Point form: (1,-3)
Equation form: x=1, y=-3
5 0
3 years ago
Please help on this one
kirill115 [55]
You just multiply g(x) and f(x) together and it gives you C :)
3 0
3 years ago
Read 2 more answers
Help me ASAP!!!!!!!!
larisa [96]

Step-by-step explanation:

a) The rule is <em><u>multiply the previous term by 6 then add 13</u></em>. So if the 1st term is n0 = -2, then the next term n1 is

n1 = 6n0 + 13

= 6(-2) + 13

= 1

n2 = 6n1 + 13

= 6(1) + 13

= 19

So the sequence goes like

-2, 1, 19

b) Now the sequence is reversed so let's write the terms as follows:

19, 1, -2

The new rule now is <em><u>subtract</u></em><em><u> </u></em><em><u>1</u></em><em><u>3</u></em><em><u> </u></em><em><u>then</u></em><em><u> </u></em><em><u>divide</u></em><em><u> </u></em><em><u>by</u></em><em><u> </u></em><em><u>6</u></em><em><u>.</u></em> You can check this as follows:

n0 = 19

n1 = (n0 - 13)/6

= (19 - 13)/6

= 1

n2 = (n1 - 13)/6

= (1 - 13)/6

= -2

5 0
3 years ago
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