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Arturiano [62]
3 years ago
13

Triangle ABC, with A = (-2,3) B = (-4,1) and C = (-3,5), is rotated 90- clockwise about the origin to make Triangle A'B'C'. What

are the y-coordinates of B'?
Mathematics
1 answer:
nikdorinn [45]3 years ago
6 0

Answer:

Step-by-step explanation:

-1

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Suppose that the manager of a company has estimated the probability of a super-event sometime during the next five years that wi
daser333 [38]

Answer:

The answer is d) 0.2303%

6 0
3 years ago
Are these figures are similar? If so, what is the scale factor?
tester [92]

Answer:

Yes, the scale factor is 0.6 repeating, or 0.7.

Step-by-step explanation:

You find the scale factor by dividing the smaller sides by the corresponding larger ones.

12/18 = 0.6 repeating

14/21 = 0.6 repeating

16/24 = 0.6 repeating

These triangles could be similar by SSS or SAS or ASA I think since congruent angles are shown in both triangles as well.

8 0
3 years ago
What is the local minimum value of the function? (Round answer to the nearest hundredth) g(x)=x^4-5x^2+4
Serhud [2]
The local minimum of function is an argument x for which the first derivative of function g(x) is equal to zero, so:
g'(x)=0
g'(x)=(x^4-5x^2+4)'=4x^3-10x=0
x(4x^2-10)=0
x=0 or 4x^2-10=0
4x^2-10=0 /4
x^2-10/4=0
x^2-5/2=0
[x-sqrt(5/2)][x+sqrt(5/2)]=0

Now we have to check wchich argument gives the minimum value from x=0, x=sqrt(5/2) and x=-sqrt(5/2).
g(0)=4
g(sqrt(5/2))=25/4-5*5/2+4=4-25/4=-9/4
g(-sqrt(5/2))=-9/4
The answer is sqrt(5/2) and -sqrt(5/2).

4 0
3 years ago
Read 2 more answers
I need help with 14 and 15
bekas [8.4K]

Answer:

14: 9 + 5 ℎ

15: − 1 6 + 9/ 9

Step-by-step explanation:

14 : ℎ ⋅ 5 + ( 9 )

5ℎ+ (9)

^^ Re-order terms so constants are on the left

5ℎ+ ⋅ 9 also 5 ℎ+9  then after this you would wanna re arange the terms so it would be 9 + 5 ℎ

7 0
3 years ago
Solve the quadratic equation 3x²-3x-1=0?<br>(by using the square method)​
ohaa [14]

Answer:

x=1 and x=-1/3

Step-by-step explanation:

3x^2-2x-1=0\\\\3(x^2-\frac{2}{3}x-\frac{1}{3})=0\\ \\3(x^2-\frac{2}{3}x-\frac{1}{3}+\frac{4}{9})=3(\frac{4}{9})\\ \\ 3(x^2-\frac{2}{3}x+\frac{1}{9})=\frac{4}{3}\\ \\ 3(x-\frac{1}{3})^2=\frac{4}{3}\\ \\(x-\frac{1}{3})^2=\frac{4}{9}\\ \\x-\frac{1}{3}=\pm\frac{2}{3}

x-\frac{1}{3}=\frac{2}{3}\\ \\x=\frac{3}{3}\\ \\x=1

x-\frac{1}{3}=-\frac{2}{3}\\ \\x=-\frac{1}{3}

Therefore, x=1 and x=-1/3

8 0
3 years ago
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