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Murrr4er [49]
3 years ago
7

Suppose that we try to solve the matrix equation AX = B by using an inverse matrix, but find that even though the matrix A is a

square matrix, it has no inverse. What can be said about the outcome from solving the associated system of linear equations by the Gauss-Jordan method?
Mathematics
1 answer:
Tanzania [10]3 years ago
7 0

Answer:

  The system will be found to be inconsistent or dependent.

Step-by-step explanation:

The matrix A will have no inverse for two different reasons:

  1. The system is inconsistent
  2. The system is dependent

In the latter case, the Gauss-Jordan method will find a set of parametric equations for a solution. In the former case, there is no solution.

The outcome will depend on the reason why there is no inverse.

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1,00000,00,00

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What’s the correct graph ?
maks197457 [2]

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The correct graph is graph E.

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3 years ago
Write the equation of the parabola that has its x-intercepts at (1+<img src="https://tex.z-dn.net/?f=%5Csqrt%7B5%7D" id="TexForm
VladimirAG [237]

Answer:

y=2x^2-4x-8

Step-by-step explanation:

<u>Factored form of a parabola</u>

y=a(x-p)(x-q)

where:

  • p and q are the x-intercepts.
  • a is some constant.

Given x-intercepts:

  • (1+√5, 0)
  • (1-√5, 0)

Therefore:

\implies y=a(x-(1+\sqrt{5}))(x-(1-\sqrt{5}))

\implies y=a(x-1-\sqrt{5})(x-1+\sqrt{5})

To find a, substitute the given point (4, 8) into the equation and solve for a:

\implies a(4-1-\sqrt{5})(4-1+\sqrt{5})=8

\implies a(3-\sqrt{5})(3+\sqrt{5})=8

\implies4a=8

\implies a=2

Therefore, the equation of the parabola in factored form is:

\implies y=2(x-1-\sqrt{5})(x-1+\sqrt{5})

Expand so that the equation is in standard form:

\implies y=2(x^2-x+\sqrt{5}x-x+1-\sqrt{5}-\sqrt{5}x+\sqrt{5}-5)

\implies y=2(x^2-x-x+\sqrt{5}x-\sqrt{5}x+\sqrt{5}-\sqrt{5}+1-5)

\implies y=2(x^2-2x-4)

\implies y=2x^2-4x-8

6 0
2 years ago
Answer==&gt;x+2<br>process?​
coldgirl [10]

Step-by-step explanation:

hope it helps . please give brainliest

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3 years ago
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