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balandron [24]
3 years ago
6

How to solve these equations?

Mathematics
1 answer:
Scorpion4ik [409]3 years ago
8 0
1) / sin x / = y ≥ 0 ;
   We solve the equation y^{2} +y - 2 = 0 ;

a = 1 ; b = 1 ; c = - 2 ;
b^{2} - 4ac = 9 ;
y1 = ( - 1 + 3 ) / 2 = 1 ≥ 0 ( correct ) ;
y2 = ( - 1 - 3 ) / 2 = - 2 ≥ 0 ( false ) ;
Then, / sin x / = 1 ;
sinx = + 1 or sin x = - 1 ;
x ∈ { 90 }  U { 270 } ;
x ∈  {90 , 270}.
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