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balandron [24]
3 years ago
6

How to solve these equations?

Mathematics
1 answer:
Scorpion4ik [409]3 years ago
8 0
1) / sin x / = y ≥ 0 ;
   We solve the equation y^{2} +y - 2 = 0 ;

a = 1 ; b = 1 ; c = - 2 ;
b^{2} - 4ac = 9 ;
y1 = ( - 1 + 3 ) / 2 = 1 ≥ 0 ( correct ) ;
y2 = ( - 1 - 3 ) / 2 = - 2 ≥ 0 ( false ) ;
Then, / sin x / = 1 ;
sinx = + 1 or sin x = - 1 ;
x ∈ { 90 }  U { 270 } ;
x ∈  {90 , 270}.
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What is the answer to this?
Dennis_Churaev [7]

Answer:

<h2>x = 14, z = 65</h2>

Step-by-step explanation:

The angles (5x - 5)° and (6x + 31)° are supplementary angles.

Supplementary Angles add up to 180°.

Therefore we have the equation:

5x - 5 + 6x + 31 = 180             <em>combine like terms</em>

(5x + 6x) + (-5 + 31) = 180

11x + 26 = 180               <em>subtract 26 from both sides</em>

11x = 154             <em>divide both sides by 11</em>

x = 14

The angles (5x - 5)° and z° are vertical angles.

Vertical angles are congruent.

Therefore we have the equation:

z = 5x - 5               <em>put x = 14 to the equation</em>

z = 5(14) - 5

z = 70 - 5

z = 65

4 0
2 years ago
Find a:27=6:11, find a​
trasher [3.6K]

Answer:

a = 14.73

Step-by-step explanation:

This ratio can also be written like this:

\frac{a}{27} = \frac{6}{11}

Then you can cross multiply to get

11a = 6 x 27

11a = 162

Divide both sides by 11

11a / 11 = 162 / 11

a = 14.73

3 0
2 years ago
Do this for brainliest! :)
frez [133]

Answer:

Question 13 is 27/2 (decimal form, 13.5, Mixed fraction 13 1/2)

Question 14 = 4

Step-by-step explanation:

hope this helped you:)

7 0
2 years ago
Explain whether this dilation is an enlargement or a reduction, and how you know. Triangle A B C is enlarged to triangle A prime
Vera_Pavlovna [14]

Answer:

the answer is:

The dilation is an enlargement because the image, triangle A'B'C', is larger than the pre-image, triangle ABC.

Step-by-step explanation:

I got it right on edge

5 0
2 years ago
Read 2 more answers
Liam is setting up folding chairs for a meeting. If he arranges the chairs in 6 rows of the same length, he
vladimir2022 [97]
We will need to have two equations here, having x as the missing length. We know that the chairs are in the same amount on each occasion, so each equation should be equal to the other.

This sets up a problem of:

6x + 7 = 4x + 13

7 and 13 being the leftover chairs and 6 and 4 being the rows. Let’s solve for x.

x = 3

Knowing this, we plug in x for one of the equations

6(3) + 7
18 + 7
25

Liam has 25 chairs.
7 0
2 years ago
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