Question

If a1= 1 and an= (an-1)^2 + 2 then find the value of a4

Answer 1

Answer:

Sequence rule:

an = (an-1)2 + 5

a1 = 4

Then:

a1 = 4

a2 = (4)2 + 5 = 16 + 5 = 21

a3 = (21)2 + 5 = 441 + 5 = 446

a4 = (446)2 + 5 = 198916 + 5 = 198921

a4 = 198,921

Answer 2

Answer:

123

Step-by-step explanation:

$a_{1}=1\\a_{n}=(a_{n-1})^2+2\\a_{2}=(a_{1})^2+2=1^2+2=1+2=3\\a_{3}=(a_{2})^2+2=3^2+2=9+2=11\\a_{4}=(a_{3})^2+2=(11)^2+2=121+2=123$