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2 years ago

15. Work out the area of a rectangle with sides 3.4cm and 4.5cm

Mathematics

2 answers:

lapo4ka [179]2 years ago

4 0

Answer:

Step-by-step explanation: Sense it's a decimal, it will be really easy.

3.4

x4.5

------

Multiply 3.4 by 5, then multiply 3.4 by 4. Add both of your answers together: 17+13.6

Your final answer should be 30.6.

pav-90 [236]2 years ago

3 0

Area is length times width so

A = 4.5*3.4 which is 15.3.

The area of the rectangle is 15.3 cm

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You serve a volleyball with a mass of 2 kg. The ball leaves your hand with a speed of 30 m/s. The ball has kinetic energy. Calcu

motikmotik

Answer:

900 j

Step-by-step explanation:

KE=1/2mv^2

so:

1/2x(2kg)x(30m/s)^2

is 900 joules. :)

6 0

3 years ago

Guys, Can you please help me with these questions

MakcuM [25]

Answer:

a) $w^{13} x^{5} y^{6}$

b) $\frac{x}{3y^{6} }$

Step-by-step explanation:

a) $(w^{2} xy^{3} )^{2}(w^{3}x )^{3}$

1. Distribute the second power (2) outside the first pair of parenthesis:

$(w^{2(2)} x^{2} y^{3(2)} )$

= $w^{4} x^{2} y^{6} (w^{3}x )^{3}$

2. Distribute the third power (3) outside the second pair of parenthesis:

$(w^{3(3)} x^{3} )$

= $w^{4} x^{2} y^{6} w^{9} x^{3}$

3. Combine like terms:

$w^{13} x^{5} y^{6}$

--------------------------------------------

b) $\frac{2x^{2} y^{5} }{6xy^{11} }$

1. Factor the number 6 (= 2 · 3):

$\frac{2x^{2} y^{5} }{2(3)xy^{11} }$

2. Cancel the common factor (2):

$\frac{x^{2} y^{5} }{3xy^{11} }$

3. Cancel out $xy^{5}$ in the numerator an denominator:

$\frac{x}{3y^{6} }$

hope this helps!

4 0

2 years ago

Two figures are similar, and the scale factor is 2/3

d1i1m1o1n [39]

Answer:

The answer is 8.

Step-by-step explanation:

The scale factor between the figures is 2/3, this means that the ratio of the smaller figure to the larger figure is 2/3:

$\frac{smaller\:figure}{larger\:figure}=\frac{2}{3}$ .

So when a side of the the larger figure is 12 then:

$\frac{smaller\:figure\: side}{12}=\frac{2}{3}$

Therefore

$smaller\:figure\:side=\frac{2}{3}*12=8$ .

Thus the length of the corresponding smaller side is 8.

3 0

3 years ago

Read 2 more answers

The volume

Sedaia [141]

$\bf \begin{array}{cccccclllll}
\textit{something}&&\textit{varies directly to}&&\textit{something else}\\ \quad \\
\textit{something}&=&{{ \textit{some value}}}&\cdot &\textit{something else}\\ \quad \\
y&=&{{ k}}&\cdot&x
&& y={{ k }}x
\end{array}\\ \quad \\
$

and also

$\bf \begin{array}{llllll}
\textit{something}&&\textit{varies inversely to}&\textit{something else}\\ \quad \\
\textit{something}&=&\cfrac{{{\textit{some value}}}}{}&\cfrac{}{\textit{something else}}\\ \quad \\
y&=&\cfrac{{{\textit{k}}}}{}&\cfrac{}{x}
&&y=\cfrac{{{ k}}}{x}
\end{array}
$

now, we know that V varies directly to T and inversely to P simultaneously
thus $\bf V=T\cdot \cfrac{k}{P}$

so $\bf V=T\cdot \cfrac{k}{P}\qquad 
\begin{cases}
V=42\\
T=84\\
P=8
\end{cases}\implies 42=\cfrac{84k}{8}\implies 4=k
\\\\\\
V=\cfrac{4T}{P}\qquad now\quad 
\begin{cases}
V=74\\
P=10
\end{cases}\implies 74=\cfrac{4T}{10}\implies 185=T$

7 0

3 years ago

When simplifying an expression using order of operations addition MUST

Rama09 [41]

Answer:

The answer is False,

Step-by-step explanation:

The answer is False because in some expressions if there are parentheses and there is a subtraction problem in the parentheses but there is an addition problem in front of the parentheses that does not exactly mean that you do the addition first, this is because the subtraction is inside the parentheses and so since the subtraction is in parentheses it is done fist.

4 0

2 years ago