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2 years ago

Carla is ordering pizzas for delivery. Each pizza costs $8 , and there is a $6 delivery charge per order.

2 answers:

6 0

F(x)= 8x+6
or f(x) = 8p+6 and p equals total number of pizzas ordered. so then theres not the same variable on both sides.

romanna [79]2 years ago

6 0

Answer:

Total cost for delivering x pizzas f(x) is given by

f (x) = 8x + 6

Step-by-step explanation:

Carla is ordering pizzas for delivery. Each pizza costs $8 , and there is a $6 delivery charge per order.

Here we need to find cost as a function of number of pizzas delivered.

Let the cost for delivering x pizzas be f(x).

Cost of 1 pizza = 8 $

Cost of x pizza = 8x $

Delivery charge = 6 $

Total cost for delivering x pizzas f(x) is given by

f (x) = 8x + 6

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Graph the equation y = x2 + 8x + 12 on the accompanying set of axes. You must

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Step-by-step explanation:

Roots: set y = x^2 + 8x + 12 = 0 and solve for x: x + 6 = 0, so x = -6 is one root. The other is x = -2. The corresponding points are (-6, 0) and (-2, 0).

y-intercept: Let x = 0. Then y = 12. The y-intercept is (0, 12).

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2 years ago

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2 years ago

Please solve these questions for me. i am having a difficult time understanding.

s2008m [1.1K]

Answer:

1) AD=BC(corresponding parts of congruent triangles)

2)The value of x and y are 65 ° and 77.5° respectively

Step-by-step explanation:

Given : AD||BC

AC bisects BD

So, AE=EC and BE=ED

We need to prove AD = BC

In ΔAED and ΔBEC

AE=EC (Given)

$\angle AED = \angel BEC$ ( Vertically opposite angles)

BE=ED (Given)

So, ΔAED ≅ ΔBEC (By SAS)

So, AD=BC(corresponding parts of congruent triangles)

Hence Proved

Refer the attached figure

$\angle ABC = 90^{\circ}$

In ΔDBC

BC=DC (Given)

So, $\angle CDB=\angle DBC$ (Opposite angles of equal sides are equal)

So, $\angle CDB=\angle DBC=x$

So, $\angle CDB+\angle DBC+\angle BCD = 180^{\circ}$ (Angle sum property)

x+x+50=180

2x+50=180

2x=130

x=65

So, $\angle CDB=\angle DBC=x = 65^{\circ}$

Now,

$\angle ABC = 90^{\circ}\\\angle ABC=\angle ABD+\angle DBC=\angle ABD+x=90$

So, $\angle ABD=90-x=90-65=25^{\circ}$

In ΔABD

AB = BD (Given)

So, $\angle BAD=\angle BDA$ (Opposite angles of equal sides are equal)

So, $\angle BAD=\angle BDA=y$

So, $\angle BAD+\angle BDA+\angle ABD = 180^{\circ}$ (Angle Sum property)

y+y+25=180

2y=180-25

2y=155

y=77.5

So, The value of x and y are 65 ° and 77.5° respectively

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3 years ago