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2 years ago

12

Look at the time on the following clocks. How much time has passed from the first clock to the second clock? The time passed is

less then 12 hours.

1 answer:

Lina20 [59]2 years ago

4 0

5 hours and 4 minutes

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Question 9 (1 point)

Luden [163]

Answer:

7

Step-by-step explanation:

16x-80+18=4x+22

16x-62=4x+22

12x-62=22

12x=84

x=7

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3 years ago

Help me plzz!!!! thank you

Maurinko [17]

Answer: The first one is 144 . The second one is C.

Step-by-step explanation:

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2 years ago

Read 2 more answers

The length of a rectangle is 3 inches more than three times it's width. Write an equation relating the length, “, of the rectang

Jobisdone [24]

An equation relating the length of the rectangle to its width would be, “l+3=w”. The length plus 3 inches would be equal to the width.

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3 years ago

Find the value of $ 15,000 at the end of one year if it is invested in an account that has an interest rate of 4.95 % and is com

lora16 [44]

A)

$\bf \qquad \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to &\$15000\\
r=rate\to 4.95\%\to \frac{4.95}{100}\to &0.0495\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{twelve months, thus}
\end{array}\to &12\\
t=years\to &1
\end{cases}
\\\\\\
A=15000\left(1+\frac{0.0495}{12}\right)^{12\cdot 1}$

b)

$\bf \qquad \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to &\$15000\\
r=rate\to 4.95\%\to \frac{4.95}{100}\to &0.0495\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{365 days, thus}
\end{array}\to &365\\
t=years\to &1
\end{cases}
\\\\\\
A=15000\left(1+\frac{0.0495}{365}\right)^{365\cdot 1}$

c)

$\bf \qquad \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to &\$15000\\
r=rate\to 4.95\%\to \frac{4.95}{100}\to &0.0495\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{four quarters, thus}
\end{array}\to &4\\
t=years\to &1
\end{cases}
\\\\\\
A=15000\left(1+\frac{0.0495}{4}\right)^{4\cdot 1}$

7 0

3 years ago

If r = 0.97, this indicates a ________ correlation. Question 10 options: A) weak negative B) weak positive C) strong negative D)

Svet_ta [14]

Answer:C

Step-by-step explanation:

A correlation of -0.97 is a strong negative correlation while a correlation of 0.10 would be a weak positive correlation

8 0

2 years ago