The bb and j was the source of the questions
There are the combinations that result in a total less than 7 and at least one die showing a 3:
[3, 3] [3,2] [2,1] [1,3] [2,3]
The probability of each of these is 1/6 * 1/6 = 1/36
There is a little ambiguity here about whether or not we should count [3,3] as the problem says "and one die shows a 3." Does this mean that only one die shows a 3 or at least one die shows a 3? Assuming the latter, the total probability is the sum of the individual probabilities:
1/36 + 1/36 + 1/36 + 1/36 + 1/36 = 5/36
Therefore, the required probability is: 5/36
Answer:
6x−12x^2
Step-by-step explanation:
Answer:
the answer is Length of each string = 195/8 inch
Total length= 100*12 = 1200 inch
Number of pieces = Total length/ Length of each piece = 1200/ (195/8)= (1200*8)/195
Step-by-step explanation:
Step-by-step explanation:
4/5 + 2/3 = 2215 = 1 715 ≅ 1.4666667. Spelled result in words is twenty-two fifteenths (or one and seven fifteenths).
