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allsm [11]
3 years ago
14

How can you approximate the square root of 30?

Mathematics
1 answer:
Ierofanga [76]3 years ago
5 0
You can approximate the square root of 30 by taking the square root of a number close to it. This is called local linearization. You can take the square root of 36, which is 6, and the square root of 25, which is 5, and state that the square root of 30 is approximately somewhere between 5 and 6
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Step-by-step explanation:

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What would the domain and range of this graph be? In interval form, if it can be.
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A plant measured x inches tall last week and 8 inches tall this week.
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Angelo earns $2,080 each month. His total deductions are 30% of his pay. How much is deducted from his pay each month? 
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Given functions f ( x ) = 1 √ x and m ( x ) = x 2 − 4 , state the domains of the following functions using interval notation.
babunello [35]

The domain of a function f(x)/m(x) = 1/√x(x² - 4) is (0, ∞) - {0, 2, -2} for other function is shown in the solution.

<h3>What is a function?</h3>

It is defined as a special type of relationship, and they have a predefined domain and range according to the function every value in the domain is related to exactly one value in the range.

We have:

f(x) =  1/√x

m(x) = x² - 4

Domain of f(x)/m(x):

f(x)/m(x) = (1/√x)/(x² - 4)

f(x)/m(x) = 1/√x(x² - 4)

The denominator cannot be zero:

√x(x² - 4) ≠ 0

x(x - 2)(x+2) ≠ 0

x ≠ 0, 2, -2

and x > 0

Domain of f(x)/m(x) is:   (0, ∞) - {0, 2, -2} or \:\left(0,\:2\right)\cup \left(2,\:\infty \:\right)

Domain of f(m(x)):

f(m(x)) = 1/√(x² - 4)

x² - 4 > 0

Domain: \rm \left(-\infty \:,\:-2\right)\cup \left(2,\:\infty \:\right)

Domain of m(f(x)):

= ((1/√x)² - 4)

Domain: \:\left(0,\:\infty \:\right)

Thus, the domain of a function f(x)/m(x) = 1/√x(x² - 4) is (0, ∞) - {0, 2, -2} for other function is shown in the solution.

Learn more about the function here:

brainly.com/question/5245372

#SPJ1

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2 years ago
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