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4 years ago

How can you approximate the square root of 30?

1 answer:

5 0

You can approximate the square root of 30 by taking the square root of a number close to it. This is called local linearization. You can take the square root of 36, which is 6, and the square root of 25, which is 5, and state that the square root of 30 is approximately somewhere between 5 and 6

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<img src="https://tex.z-dn.net/?f=-6%5Cleft%281-m%5Cright%29%3D9-2m" id="TexFormula1" title="-6\left(1-m\right)=9-2m" alt="-6\le

Musya8 [376]

Answer:

$m=\frac{15}{8}$

Step-by-step explanation:

$-6\left(1-m\right)=9-2m$

$-6(1-m)=-6+6m$

$-6+6m=9-2m$

Add 6 to both sides:-

$-6+6m+6=9-2m+6$

$6m=-2m+15$

Now, add 2m to both sides:-

$6m+2m=-2m+15+2m$

Divide both sides by 8:-

$\frac{8m}{8}=\frac{15}{8}$

$m=\frac{15}{8}$

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3 years ago

Read 2 more answers

HELP!

jeka94

Answer:

The answer to this question can be described as follows:

Step-by-step explanation:

Given equation:

$\bold{0.5x-7= \sqrt{(-5x+29)}}$

As in the given question the two ways to solve the equation can be defined as follows:

First way:

Let square the above-given equation then we will get:

$\to (0.5x-7)^2= (\sqrt{(-5x+29)})^2\\\\\to (0.5x)^2 +7^2-2\times 0.5x\times 7= -5x+29\\\\\to 0.25x^2 +49- 7x= -5x+29\\\\\to 0.25x^2 - 7x+5x +49-29=0\\\\\to 0.25x^2 - 2x+20=0\\\\$