Question

Answer please tomorrow is my

Answer 1

This is easier than it looks!

Remember: $(a+b)^2 = a^2+2ab+b^2$

and (a+b) is given and we have one ab too much...

So:$a^2+ab+b^2 = (a+b)^2 - ab = 10^2 - 16 = 84$

If we subtract ab twice more, we got the other one.

$a^2-ab+b^2 = (a+b)^2 - 3ab = 10^2 - 3 \cdot 16 = 52$