2 years ago

HELP WHAT IS THE SLOPE OF THIS GRAPH!!! DUE TODAY ALMOST LATE!!!!!

Mathematics

2 answers:

Alborosie2 years ago

8 0

It’s 5/2
Rise/ run
Rise of 5
Run of 2

Nady [450]2 years ago

6 0

Answer:

wait what?

how is something meant to be due late, like b r u h you can't make a task due late. LOL :)

Step-by-step explanation:

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SVETLANKA909090 [29]

Ya what the person above me said

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2 years ago

The coordinates of the vertices of AJKL are J(-5, -1), K(0, 1), and L(2, -5).

dalvyx [7]

We need slope of all lines ?

J(-5,-1)
K(0,1)
L(2,-5)

Slope of JK:-

$\\ \sf\longmapsto m=\dfrac{1+1}{0+5}=\dfrac{2}{5}$

Slope of KL:-

$\\ \sf\longmapsto m=\dfrac{-5-1}{2-0}=\dfrac{-6}{0}=-3$

Slope of JL

$\\ \sf\longmapsto m=\dfrac{-5-1}{2+5}=\dfrac{-6}{7}$

7 0

2 years ago