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s2008m [1.1K]
2 years ago
12

HELP WHAT IS THE SLOPE OF THIS GRAPH!!! DUE TODAY ALMOST LATE!!!!!

Mathematics
2 answers:
Alborosie2 years ago
8 0
It’s 5/2
Rise/ run
Rise of 5
Run of 2
Nady [450]2 years ago
6 0

Answer:

wait what?

how is something meant to be due late, like b r u h you can't make a task due late. LOL :)

Step-by-step explanation:

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Need help with number 10 please
Naddika [18.5K]

Answer:

  Pilar is correct. Both systems have solution (-2, 4).

Step-by-step explanation:

Graphing, or any other means of solving these systems of equations reveals both systems have the same solution: (x, y) = (-2, 4).

_____

By Cramer's rule, the solution to the first set is ...

  x = (2(6)-4(2))/(2(5)-4(3)) = 4/-2 = -2

  y = (2(5)-6(3))/-2 = -8/-2 = 4

(x, y) = (-2, 4) is the solution to the first system

__

Since the first equation of the second system is the same as the first equation of the first system, we know the above solution satisfies that equation. We only need to check to see if the same point satisfies the second equation of the second system:

  11(-2) +8(4) = -22 +32 = 10 . . . . . yes,

(-2, 4) is the solution of the second system

Pilar is correct that both systems have the same solution.

_____

Cramer's Rule tells you the solution to

  • ax +by = c
  • dx +ey = g

is ...

  • x = (bg -ec)/(bd -ea)
  • y = (cd -ga)/(bd -ea) . . . . same denominator as for x

I like to use Cramer's Rule when the solution is needed without a lot of steps. Here, we could use the Elimination method to eliminate the y-variable and solve for x. Then more steps are needed to find y. The writing out and explanation are tedious, so it is much simpler just to use a formula that gives the answer.

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3 years ago
Which of the following is a rule for a rotation?
Nata [24]

Answer:

Hiiiii, the answer is (x,-y)

Step-by-step explanation:

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daser333 [38]
2x + 1

You can find that by switching the signs in the second set of parenthesis and then adding. 
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Answer: d 10900

Step-by-step explanation:

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Answer:

the correct answer is A.) on edg

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