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sdas [7]
3 years ago
6

What is the answer??????​

Chemistry
2 answers:
kakasveta [241]3 years ago
5 0

Answer:

I think it will be true. But I'm not sure.

Shalnov [3]3 years ago
4 0

Answer:

I think so It's true

let's me check

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When a solution of 0.1 M Mg(NO3)2 was mixed with a limited amount of aqueous ammonia, a light white, wispy solid was observed, i
Ipatiy [6.2K]

<u>Answer:</u> The net ionic equation is written below.

<u>Explanation:</u>

Net ionic equation of any reaction does not include any spectator ions.

Spectator ions are defined as the ions which does not get involved in a chemical equation. They are found on both the sides of the chemical reaction when it is present in ionic form.

The chemical equation for the reaction of magnesium nitrate and aqueous ammonia (ammonium hydroxide) is given as:

Mg(NO_3)_2(aq.)+2NH_4OH(aq.)\rightarrow Mg(OH)_2(s)+2NH_4NO_3(aq.)

A white precipitate of magnesium hydroxide is formed in the above reaction.

Ionic form of the above equation follows:

Mg^{2+}(aq.)+2NO_3^-(aq.)+2NH_4^+(aq.)+2OH^-(aq.)\rightarrow Mg(OH)_2(s)+2NH_4^+(aq.)+2NO_3^-(aq.)

As, ammonium and nitrate ions are present on both the sides of the reaction. Thus, it will not be present in the net ionic equation and are spectator ions.

The net ionic equation for the above reaction follows:

Mg^{2+}(aq.)+2OH^-(aq.)\rightarrow Mg(OH)_2(s)

Hence, the net ionic equation is written above.

8 0
3 years ago
​What is the concentration of the solution prepared by dissolving 2.35 g of KBr (M = 119 g/mol) in 250 mL of water? 
dusya [7]

Answer:

The concentration of KBr is  C = 0.07899 \ mol   L^{-1}

Explanation:

From the question we are told that

      The mass of KBr is  m_{KBr}  = 2.35 \ g

       The molar mass of KBr is  M_{KBr} =  119 g/mol

       Volume of water is V = 250 \ mL = 250 *10^{-3} =  0.250 \ L

This implies that the volume of  the solution is  V = 250 mL

The number of moles of KBr is

         n = \frac{m_{KBr}}{M_{KBr}}

Substituting values

         n =  \frac{2.35}{119}

        n = 0.01975 \ mol

The concentration of KBr is mathematically represented as

                C = \frac{0.01975}{0.250}

                C = 0.07899 \ mol   L^{-1}

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4 years ago
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</span>That is because hydrogen bonds between water molecules in glaciers is decreased under increasing concentrations of carbon dioxide who <span>competes with the water molecules connected in the ice crystal.</span>
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