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barxatty [35]
3 years ago
9

Hydrogen is manufactured on an industrial scale by this sequence of reactions:

Chemistry
1 answer:
hichkok12 [17]3 years ago
6 0

Answer:

K=K_1*K_2\\\\K=\frac{[H_2]^3[CO_2][H_2]}{[CH_4][H_2O][H_2O]}

Explanation:

Hello there!

In this case, for the given chemical reaction, it turns out firstly necessary to write the equilibrium expression for both reactions 1 and 2:

K_1=\frac{[CO][H_2]^3}{[CH_4][H_2O]} \\\\K_2=\frac{[CO_2][H_2]}{[CO][H_2O]}

Now, when we combine them to get the overall expression, we infer these two are multiplied to get:

K=K_1*K_2\\\\K=\frac{[CO][H_2]^3}{[CH_4][H_2O]} *\frac{[CO_2][H_2]}{[CO][H_2O]}\\\\K=\frac{[H_2]^3[CO_2][H_2]}{[CH_4][H_2O][H_2O]}

Regards!

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Explanation:

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N2 + 3H2 ⇒ 2 NH_{3}

Given

mass of ammonia in 1 bottle of windex = 51 gram

atomic mass of ammonia 17.01 gram/mole

number of moles = \frac{mass}{atomic mass of 1 mole}

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in 1 bottle of windex there are 3 moles of ammonia 0r 51 grams of ammonia.

From the equation it can be found that:

3 moles of hydrogen reacted to form 2 moles of ammonia

so, x moles of hydrogen will react to form 3 moles of ammonia.

\frac{2}{3} = \frac{3}{x}

x = 4.5 moles of hydrogen will be required.

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mass = atomic mass x number of moles  (atomic mass of H2 is 2grams/mole)

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A partial orbital diagram shows only the highest energy sublevels being filled. Al (Z = 13) 1s22s22p63s23p1. A condensed electron configuration has the element symbol of the previous noble gas in square brackets. Al has the condensed configuration [Ne]3s23p1.

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