Answer:
a)NaBr
b)FCl
Explanation:
To identify which compound is more ionic we will calculate the electronegativity difference.
A) NaBr
Electronegativity of Na = 0.93
Electronegativity of Br = 2.96
Electronegativity difference = 2.96- 0.93 = 2.03
HBr
Electronegativity of H = 2.2
Electronegativity of Br = 2.96
Electronegativity difference = 2.96 - 2.2 = 0.76
NaBr have more ionic character because of large electronegativity difference.
B) BrCl
Electronegativity of Cl = 3.16
Electronegativity of Br = 2.96
Electronegativity difference = 3.16 - 2.96 = 0.2
FCl
Electronegativity of F = 3.98
Electronegativity of Br = 2.96
Electronegativity difference = 3.98 - 2.96 = 1.02
FCl have more ionic character because of large electronegativity difference.
