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m_a_m_a [10]
3 years ago
14

Which equation describes a relationship such that x = 0 must be excluded from the domain?

Mathematics
2 answers:
zalisa [80]3 years ago
7 0

Answer:

Example: f(x) = (1 + x + x^2) / x, x=0 is excluded from the domain, since division by zero is undefined.

Step-by-step explanation:

Soloha48 [4]3 years ago
5 0
This is because it only has an x-intercept and does not intersect they-axis. Vertical lines cannot be written in standard form because the slope is undefined. The equation of the line is given by the x-intercept of the line. In this case x=0 goes though the origin (x=0), which means this is the equation of the y-axis
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Stella is ordering a taxi from an online taxi service. The taxi charges $3 just for the pickup and then an additional $1.75 per
user100 [1]

Answer:

$ 6.50

Step-by-step explanation:

Based on the given conditions, formulate 3+2 × 1.75

calculate the first two terms 3+3.5

calculate the first two terms 6.5

Answer: 6.5

8 0
3 years ago
Coffee with sugar and milk added to it can contain up to calories. To consume a maximum of 600 mg if caffeine per day, how many
Marina CMI [18]
We know there is 330 mg of caffeine per 16-ounce serving. So if we want 8-ounce servings:
330 mg : 2 = 165 mg
Also we have to consume a maximum of 600 mg.
165 mg * 3 = 495 mg < 600 mg
165 mg * 4 = 660 mg > 600 mg
Answer: Someone could drink 3 full 8-ounce servings in a day and still stay below the limit.
8 0
3 years ago
Read 2 more answers
In the function f(t) = sin(t), what is the effect of multiplying t by a coefficient of 2?
liubo4ka [24]

Answer:

"changes the period to pi"

Step-by-step explanation:

f(t) = Sin(t),

Here, t is the period, by definition.

Multiply t by a number that is GREATER THAN 1, makes the period shorter and compressed.

Multiplying t by a number that is between 0 and 1 makes the period expanded.

For the first, if we multiply the period by a, the period becomes \frac{2\pi}{a}

Since the problem tells us to multiply by 2, we know the period becomes compressed and becomes :

\frac{2\pi}{2}=\pi

Third answer choice is right.

5 0
3 years ago
Anyone know how to do this??
nevsk [136]

Answer:

x=5ft

Step-by-step explanation:

3 is half of 6, so triangle DEF is half as big as triangle ABC. Hope this helps.

5 0
3 years ago
Which is the simplified form of the expression ((2 Superscript negative 2 Baseline) (3 Superscript 4 Baseline)) Superscript nega
AlekseyPX

Answer:

The option "StartFraction 1 Over 3 Superscript 8" is correct

That is \frac{1}{3^8} is correct answer

Therefore [(2^{-2})(3^4)]^{-3}\times [(2^{-3})(3^2)]^2=\frac{1}{3^8}

Step-by-step explanation:

Given expression is ((2 Superscript negative 2 Baseline) (3 Superscript 4 Baseline)) Superscript negative 3 Baseline times ((2 Superscript negative 3 Baseline) (3 squared)) squared

The given expression can be written as

[(2^{-2})(3^4)]^{-3}\times [(2^{-3})(3^2)]^2

To find the simplified form of the given expression :

[(2^{-2})(3^4)]^{-3}\times [(2^{-3})(3^2)]^2

=(2^{-2})^{-3}(3^4)^{-3}\times (2^{-3})^2(3^2)^2 ( using the property (ab)^m=a^m.b^m )

=(2^6)(3^{-12})\times (2^{-6})(3^4) ( using the property (a^m)^n=a^{mn}

=(2^6)(2^{-6})(3^{-12})(3^4) ( combining the like powers )

=2^{6-6}3^{-12+4} ( using the property a^m.a^n=a^{m+n} )

=2^03^{-8}

=\frac{1}{3^8} ( using the property a^{-m}=\frac{1}{a^m} )

Therefore [(2^{-2})(3^4)]^{-3}\times [(2^{-3})(3^2)]^2=\frac{1}{3^8}

Therefore option "StartFraction 1 Over 3 Superscript 8" is correct

That is \frac{1}{3^8} is correct answer

6 0
4 years ago
Read 2 more answers
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