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Serjik [45]
3 years ago
14

(3-2sqrt-18)-(2+3sqrt-8)​

Mathematics
1 answer:
Mama L [17]3 years ago
7 0
Tell me the question and I’ll help you with it is it simplify or evalute etc.
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(12x - 2y + 3/5) - (1/4 - 8x + 6y)
Neko [114]

Answer:

20x-8y+ 7/20

Step-by-step explanation:

7 0
3 years ago
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Solve z=9/13 c for c
andreev551 [17]

Answer:

3x-x+2=4 :)

Step-by-step explanation:

Hope this helped! :3

4 0
2 years ago
5. Use any method to solve the equation. If necessary, round to the nearest hundredth.
DanielleElmas [232]

Answer:

2.45, -2.45

Step-by-step explanation:

Since the equation has only one term in the unknown "x", we can solve for it isolating "x" on one side of the equal sign:

8x^2-48=0\\8x^2=48\\x^2=\frac{48}{8} \\x^2=6\\x=+/-\sqrt{6} \\x=+/- 2.449

Which we can round to: x = - 2.45 and x = 2.45

7 0
3 years ago
Write a 3-digit number using the digits 5,9,and 2. Then write your number using words.
viva [34]

592, five ninety two

3 0
3 years ago
Read 2 more answers
I NEED HELP PLEASE <br> ITS DUE SOOM
tekilochka [14]

Answer:

Tyler is correct. The temperature dropped at a rate of about 4° per hour between 4 and 6, while the temperature dropped at about 2.25° per hour between 6 and 10.

Edit: Explanation

The question is asking about which window of time had a <em>faster</em> decline in temperature, not a larger total change in temperature.

In a 2 hour timeframe, the temperature dropped 8°. (4-6 PM)

In a separate 4 hour timeframe, the temperature dropped 9°. (6-10 PM)

To find which window had a faster change in temp, I took the total temperature drop for each timeframe, then divided it by the number of hours each drop took.

8° / 2 = 4° per hour for 4-6 PM

9° / 4 = 2.25° per hour from 6-10 PM

Since the speed at which the temperature dropped per hour was greater from 4-6 PM than 6-10 PM, Tyler was correct.

6 0
3 years ago
Read 2 more answers
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