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Angelina_Jolie [31]
4 years ago
12

What is an irrational number between 5.2 and 5.5?

Mathematics
1 answer:
Mila [183]4 years ago
4 0
5.2 \ \textless \  x \ \textless \  5.5 \\  \\ \sqrt{5.2^2} \ \textless \  \sqrt{x^2} \ \textless \  \sqrt{5.5^2} \\  \\ \sqrt{27.04} \ \textless \  \sqrt{x^2} \ \textless \  \sqrt{30.25}

Let x^2 be any whole number between 27.04 and 30.25.

x^2 = 29 \\  \\ x = \sqrt{29}
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Kisachek [45]

Answer:

7^{\frac{2}{5}}

Step-by-step explanation:

Step 1: First apply radical rule in the given expression.

\sqrt[n]{a}=a^{\frac{1}{n}}

Here, \sqrt[3]{7}=7^{\frac{1}{3}}, \sqrt[5]{7}=7^{\frac{1}{5}}

The expression becomes \frac{\sqrt[3]{7}}{\sqrt[5]{7}}=\frac{7^{\frac{1}{3}}}{7^{\frac{1}{5}}}  

Step 2: Now, apply exponent rule in the above expression

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So, the expression becomes, 7^{\left(\frac{1}{3}-\frac{1}{5}\right)}.

Step 3: Take cross multiply the denominator and numerator of the fraction in the power of 7.

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The answer is 7^{\frac{2}{5}}.

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Read 2 more answers
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