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NeTakaya
3 years ago
11

HELPPP PLZZZ Answer the last question.

Mathematics
2 answers:
g100num [7]3 years ago
5 0
I think 10lmk I don’t know tho sry
velikii [3]3 years ago
3 0

Answer:

i think it's 10 lmk if it's wrong lol

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Anyone know the answer?
Stolb23 [73]

Answer:

y-intercept = 1

Step-by-step explanation:

Here 1 grids crossing means increasing or decreasing by 1 grid. Here we are seeing the line crosses 1 grid above 0. So its positive 1. From here we find the y intercept is +1. Line crosses at coordinate ( 0 , 1 )

8 0
2 years ago
Read 2 more answers
WILL GIVE BRAINLIEST!!<br> only if you explain ur answer
FromTheMoon [43]
What’s the question LOLOL.
8 0
3 years ago
What is true of the graph of two lines 3y-8=-5x and 6y=-10x+16
Murljashka [212]

Answer:

Both lines are equal (they are the same)

<em></em>

Step-by-step explanation:

Given

3y - 8 = -5x

6y = -10x + 16

Required

What is true about graph of both lines

<em>Questions like this are better solved when there's option(s) to select from. However, some of the properties of line equation that I'll consider are to check  if both lines are either parallel or perpendicular</em>

<em />

To do this,

The first thing to do is to calculate the slope of both lines

3y - 8 = -5x

Add 8 to both sides

3y - 8 + 8 = -5x + 8

3y = -5x + 8

Divide both sided by 3

\frac{3y}{3} = -\frac{5x}{3} + \frac{8}{3}

y = -\frac{5x}{3} + \frac{8}{3}

The slope of the line is the coefficient of x;

Slope = -\frac{5}{3}

Solve for the y intercept; <em>Let x = 0</em>

y = -\frac{5 * 0}{3} + \frac{8}{3}

y = 0 + \frac{8}{3}

y = \frac{8}{3}

Solve for the x intercept; <em>Let y = 0</em>

0 = -\frac{5x}{3} + \frac{8}{3}

Subtract \frac{8}{3} from both sides

0 - \frac{8}{3} = -\frac{5x}{3} + \frac{8}{3} - \frac{8}{3}

- \frac{8}{3} = -\frac{5x}{3}

Subtract both sides by -\frac{3}{5}

-\frac{3}{5}*- \frac{8}{3} = -\frac{5x}{3} * -\frac{3}{5}

-\frac{3}{5}*- \frac{8}{3} = x

\frac{3}{5} * \frac{8}{3} = x

\frac{8}{5} = x

x = \frac{8}{5}

------------------------------------------------------------------------------------------------------

6y = -10x + 16

Divide both sides by 6

\frac{6y}{6} = -\frac{10x}{6} + \frac{16}{6}

y = -\frac{10x}{6} + \frac{16}{6}

Simplify fractions to lowest term

y = -\frac{5x}{3} + \frac{8}{3}

The slope of the line is the coefficient of x;

Slope = -\frac{5}{3}

Solve for the y intercept; <em>Let x = 0</em>

y = -\frac{5 * 0}{3} + \frac{8}{3}

y = 0 + \frac{8}{3}

y = \frac{8}{3}

Solve for the x intercept; <em>Let y = 0</em>

0 = -\frac{5x}{3} + \frac{8}{3}

Subtract \frac{8}{3} from both sides

0 - \frac{8}{3} = -\frac{5x}{3} + \frac{8}{3} - \frac{8}{3}

- \frac{8}{3} = -\frac{5x}{3}

Subtract both sides by -\frac{3}{5}

-\frac{3}{5}*- \frac{8}{3} = -\frac{5x}{3} * -\frac{3}{5}

-\frac{3}{5}*- \frac{8}{3} = x

\frac{3}{5} * \frac{8}{3} = x

\frac{8}{5} = x

x = \frac{8}{5}

-------------------------------------------------------------------------------------------------------

By comparing the slope, x intercept and y intercept of both lines;

It'll be observed that they have the same slope, x intercept and y intercept

<em>This implies that both lines are equal; in other words, they are the same.</em>

6 0
3 years ago
Will mark brainliest
Lilit [14]

(2x+1)+(3x-5)=5x-4 you just have to try some of them out and see which ones work

5 0
3 years ago
three bags of sweets weigh 27/4 kg. two of them have the same weight and the third bag is heavier than each of the bags of equal
Nana76 [90]

I'm here buddy,

so, let's take the value of the two bags with equal weight as x.

=     x + x + (x + \frac{6}{5}) = \frac{27}{4}

=     3x + \frac{6}{5} = \frac{27}{4}

=     3x = \frac{27}{4} - \frac{6}{5}

( let's take the LCM of 4 and 5 = 20

=     3x = \frac{135}{20} - \frac{24}{20}

=     3x = \frac{111}{20}

=       x = \frac{111}{20} ÷ \frac{3}{1} = \frac{111}{20} × \frac{1}{3} = \frac{37}{20}

So, the weight of the equal bags are \frac{37}{20} and the weight of the third bag ( heavy one ) is \frac{37}{20} + \frac{6}{5} = \frac{37}{20} + \frac{24}{20} = \frac{61}{20}

1st bag =     \frac{37}{20} kg

2nd bag =  \frac{37}{20} kg

3rd bag =   \frac{61}{20} kg

Hope it helps...

7 0
3 years ago
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