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3 years ago

5

How to find out the independent variable and dependent variable from a graph?

1 answer:

I am Lyosha [343]3 years ago

6 0

Answer:

The Axes. The independent variable belongs on the x-axis the(horizontal line) of the graph and the dependent variable belongs on the y-axis the (vertical line)

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A regular 24-sided polygon is rotated with its center of rotation at its center.

Svetach [21]

The smallest degree of rotation is called the angle of rotation. This can be calculated by dividing the angle of full rotation by the number of sides of a regular polygon. Since a full rotation is 360 degrees, we divide 360 by 24.

Thus, the smallest rotation needed to map the polygon back to itself is 15 degrees.

8 0

3 years ago

Read 2 more answers

Maureen went on a 3 day, 50 mile biking trip. The first day she biked 6 miles. The second day she

abruzzese [7]

Step-by-step explanation:

Given

d1 = 6 miles

d2 = 19 miles

d3 = ?

d1+d2+d3 = 50

6+19+d3 = 50

25+d3 = 50

d3 = 50 - 25

= 25miles

7 0

3 years ago

What is the domain and range for {(63, 54), (45, 36), (27, 18), (9, 0)}.

yawa3891 [41]

Range= 54,36,18,0
Domain= 63,45,27,9

5 0

3 years ago

Read 2 more answers

A random sample of 20 students from both the Science and Math club were surveyed about what supplies they would like to purchase

alekssr [168]

Answer:

<u>84 students </u>

Step-by-step explanation:

See the attached table

As shown there are 20 students from Math club, 7 of them would like to choose calculators.

so, the probability of students who choose calculators = 7/20

If there are 240 students in the Math club

So, the number of students expected to choose calculators = 240 * 7/20

<u>So, the number of students = 84 students </u>

6 0

3 years ago

PLEASE ANSWER ASAP!!!!

Arlecino [84]

We'll use the notation $\textrm{Arcsin } x$ for the principal value and $\arcsin x$ for all the values:

$\arcsin x = \textrm{Arcsin } x + 2\pi k \textrm{ or } (\pi - \textrm{Arcsin }x) + 2\pi k \quad \textrm{ integer } k$

Part I

$\sin(\theta/2) = \frac 1 2$

$\theta/2 = \arcsin \frac 1 2$

Part II. In our range we can write

$\sin(\theta/2) = \sin(\frac \pi 6)$

$\theta/2 = \frac \pi 6 \textrm{ or } \theta /2 = \pi - \frac \pi 6 = \frac{5\pi}{6}$

Part III.

$\theta = \frac \pi 3 \textrm{ or } \theta = \frac{5\pi}{3}$

Part IV.

$\theta/2 = \frac \pi 6 + 2\pi k \textrm{ or } \theta = \frac{5 \pi}{6} + 2\pi k \quad \textrm{integer } k$

$\theta = \frac \pi 3 + 4 \pi k \textrm{ or } \theta = \frac{5 \pi}{3} + 4\pi k \quad \textrm{integer } k$

5 0

3 years ago