Abertura formada por dos<br> semi-rectas con un mismo<br> origen llamado vértice.

A chemist has a solution of 65% pure acid and another solution of 30% pure acid. How many gallons of each will make 350 gallons

AysviL [449]

Answer:

250 of 65% acid

100 gallons of 30% acid

Really sorry if this is incorrect, I had this question on my Lesson 16 test, and I don't know if it's correct or not...

8 0

2 years ago

Read 2 more answers

Help me with this exponent problem thanks <br><br> Srry for the bad quality

irakobra [83]

Hi! Could you type the question out.

7 0

3 years ago

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What is the product?

alexdok [17]

Answer: C

Explanation:i got it right on my test

4 0

1 year ago

The standard diameter of a golf ball is 42.67 mm. A golf ball factory does quality control on the balls it manufactures. Golf ba

sergiy2304 [10]

THE ANSWER IS A:

This is the function:

f(x)=|42.67-x|.

42.670 -.002 =42.668

42.668 mm to 42.670

Explanation:

Production will be stopped if the difference in diameter is greater than 0.002 mm.

This difference can mean that the golf ball has a diameter more than 0.002 larger than 42.67 mm, or a diameter more than 0.002 smaller than 42.67. This is the reason for using an absolute value function.

Absolute value represents the distance a number is from 0. For this function, we would want only the values where the function is less than 0.002.

4 0

3 years ago

After an antibiotic tablet is taken, the concentration of the antibiotic in the bloodstream is modelled by the function C(t)=8(e

Alexxx [7]

Answer:

the maximum concentration of the antibiotic during the first 12 hours is 1.185 $\mu g/mL$ at t= 2 hours.

Step-by-step explanation:

We are given the following information:

After an antibiotic tablet is taken, the concentration of the antibiotic in the bloodstream is modeled by the function where the time t is measured in hours and C is measured in $\mu g/mL$

$C(t) = 8(e^{(-0.4t)}-e^{(-0.6t)})$

Thus, we are given the time interval [0,12] for t.

We can apply the first derivative test, to know the absolute maximum value because we have a closed interval for t.
The first derivative test focusing on a particular point. If the function switches or changes from increasing to decreasing at the point, then the function will achieve a highest value at that point.

First, we differentiate C(t) with respect to t, to get,

$\frac{d(C(t))}{dt} = 8(-0.4e^{(-0.4t)}+ 0.6e^{(-0.6t)})$

Equating the first derivative to zero, we get,

$\frac{d(C(t))}{dt} = 0\\\\8(-0.4e^{(-0.4t)}+ 0.6e^{(-0.6t)}) = 0$

Solving, we get,

$8(-0.4e^{(-0.4t)}+ 0.6e^{(-0.6t)}) = 0\\\displaystyle\frac{e^{-0.4}}{e^{-0.6}} = \frac{0.6}{0.4}\\\\e^{0.2t} = 1.5\\\\t = \frac{ln(1.5)}{0.2}\\\\t \approx 2$

At t = 0

$C(0) = 8(e^{(0)}-e^{(0)}) = 0$

At t = 2

$C(2) = 8(e^{(-0.8)}-e^{(-1.2)}) = 1.185$

At t = 12

$C(12) = 8(e^{(-4.8)}-e^{(-7.2)}) = 0.059$

Thus, the maximum concentration of the antibiotic during the first 12 hours is 1.185 $\mu g/mL$ at t= 2 hours.

4 0

2 years ago

Abertura formada por dos semi-rectas con un mismo origen llamado vértice.