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2 years ago

List the final state of the cache, with each valid entry represented as a record of < index, tag, data >.

1 answer:

8 0

There is not enough information to give correct answer. Anyway, I guess, I've seen this question before and I know the answer. I wrote it in binary. So if your task's details look like this: tag bits 31-10 2; index bits 9-4; offset bits 3:0; your answer is:

<000000, 0001, mem[1024]>
<000001, 0011, mem[3088]>
<001011, 0000, mem[176]>
<001000, 0010, mem[2176]>
<001110, 0000, mem[224]>
<001010, 0000, mem[160]>

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Answer:

C code is given below

Explanation:

// Define a function UpdateTimeWindow() with parameters timeStart, timeEnd, and offSetAmount. Each parameter is of type int. The function adds offSetAmount to each of the first two parameters. Make the first two parameters pass-by-pointer. Sample output for the given program:

#include <stdio.h>

// Define void UpdateTimeWindow(...)

void UpdateTimeWindow(int*timeStart, int* timeEnd, int offSetAmount){

*timeStart = *timeStart+ offSetAmount;

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}

int main(void) {

int timeStart = 0;

int timeEnd = 0;

int offsetAmount = 0;

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offsetAmount = 2;

printf("timeStart = %d, timeEnd = %d\n", timeStart, timeEnd);

UpdateTimeWindow(&timeStart, &timeEnd, offsetAmount);

printf("timeStart = %d, timeEnd = %d\n", timeStart, timeEnd);

return 0;

}

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