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statuscvo [17]
2 years ago
9

How many grams of KClO3 are needed to make 30.0 g of KCI?

Chemistry
1 answer:
lawyer [7]2 years ago
6 0

Answer:

2KClO3 ==> 2 KCl + 3O2

393g O2 x 1 mole/32 g = 12.28 moles O2

moles KClO3 needed = 12.28 mol O2 x 2 mol KClO3/3mol O2 = 8.19 mol

grams KClO3 = 8.19 moles x 123g/mol = 1007g

Explanation:

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