Heat required = 173 kJ
<h3>Further explanation</h3>
Given
56.0 g of ice
Temperatur at 263 K(-10 C) to 400 K(127 C)
Required
Heat needed
Solution
1. raise the temperature(-10 C to 0 C)⇒c ice=2.09 J/g C
2. phase change (ice to water)⇒Heat of fusion water=334 J/g
3. raise the temperature(0 C to 100 C)⇒c water= 4.18 J/g C
4. phase change(water to vapor)⇒heat of vaporization water=2260 J/g
5. raise the temperature(100 C to 127 C)⇒c vapor=2.09 J/g C
Total heat :
1170.4+18704+23408+126560+3160.08=173,002.48 J=173 kJ
The number of moles present in the FeSO4 are 0.055 mol.
<u>Explanation:</u>
- The mass of a substance containing the same number atoms in 12.0 g of 12C is known as mole. One mole of any substance is equal to 6.023 x 10^23. The moles of a substance can be determined by using the formula,
Number of moles = mass in grams / molecular mass
Given,
mass = 8.36 g,
molecular mass of FeSO4 = 151.908 g / mol
number of moles = 8.36 / 151.908
= 0.055 mol.
A mixture is a portion of matter made up of two or more substances called constituents. Mixtures are the product of the mechanical joining of substances without change in chemical nature, and therefore, each constituent retains its properties.
the option 4
Answer: An acid is defined with having more [H₃O+] ions, and a base is defined with having more [OH-] ions. On the pH scale, an acid has a lower pH and a base has a higher pH. With this being said, the lower the pH, the more [H₃O+] ions are present and the higher the pH, the more [OH-] ions are present.
Explanation:
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