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Afina-wow [57]
4 years ago
15

What is the ph of a solution that consists of 0.50 m h2c6h6o6 (ascorbic acid) and 0.75 m nahc6h6o6 (sodium ascorbate)? ka = 6.8

´ 10-5 question 12 options: 1) 3.76 2) 3.99 3) 4.34 4) 4.57 5) 5.66?
Chemistry
1 answer:
bearhunter [10]4 years ago
4 0

Answer:

4.34.

Explanation:

  • For acidic buffer:

<em>∵ pH = pKa + log [salt]/[Acid]</em>

∴ pH = - log(Ka) + log [salt]/[Acid]

∴ pH = - log(6.8 x 10⁻⁵) + log(0.75)/(0.50)

<em>∴ pH = 4.167 + 0.176 = 4.343 ≅ 4.34.</em>

<em></em>

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SEP Analyze Data Use graphing software or draw a graph from the data in the table. Label "Heat input (joules)" on the y-axis and
galben [10]

The characteristics of the graphic representation are to find the scales and make the best graphic, in the attachment we have the points plotted

The graphical representation is one of the best methods to see the relationships between groups of data and to be able to find the functional relationships between them.

In this case, it is requested to make a scatter plot where the measured temperature is placed on the x-axis and the heat on the y-axis.

In the attachment we can see a graph with the requested data, the most important part of finding these graphs is looking for the scales

x-axis

          scale x = \frac{\Delta Values}{paper length}

y-axis

          scale y = \frac{\Delta Values}{paper \ lengthy}

In general, the paper is 20 x 30 cm, we select the shortest part as the x axis

         scale x = \frac{50-30}{20}

         scale x = 1º  \frac{ C}{cm \ peper}  

         

Let's find the scale on the axis and the maximum value is 54000 and the minimum value is 3800, as the minimum value is much less than the maximum value, let's set this value to zero

         scale y = \frac{54000-0}{30}

         scale y = 1800  \frac{j}{cm \ paper}

To facilitate marking the values, we select a slightly larger scale,

Selected scale

           scale y = 2000 \frac{j}{cm \ paper}

Let's mark the points.

From observing these graph we see;

  • The relationships are linear
  • For the same material the amount of heat necessary to reach the same temperature is proportional to the mass of the material

Using the characteristics of the graphical representation, it is possible to find the scales and make the best graph

Learn more here: brainly.com/question/12511806

6 0
3 years ago
An aqueous solution is prepared by dissolving 15.6 g of Cu(NO3)2 ⋅ 6 H2O in water and diluting to 345 mL of solution. What is th
Vladimir [108]

<u>Answer:</u> The molarity of NO_3^- ions in the solution is 0.306 M

<u>Explanation:</u>

To calculate the molarity of solution, we use the equation:

\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}

We are given:

Mass of solute (Cu(NO_3)_2.6H_2O) = 15.6 g

Molar mass of (Cu(NO_3)_2.6H_2O) = 295.6 g/mol

Volume of solution = 345 mL

Putting values in above equation, we get:

\text{Molarity of }Cu(NO_3)_2.6H_2O=\frac{15.6g\times 1000}{295.6g/mol\times 345mL}\\\\\text{Molarity of }Cu(NO_3)_.6H_2O=0.153M

As, 1 mole of (Cu(NO_3)_2.6H_2O) produces 1 mole of copper (II) ions and 2 moles of nitrate ions.

So, molarity of NO_3^- ions = (2 × 0.153) = 0.306 M

Hence, the molarity of NO_3^- ions in the solution is 0.306 M

3 0
3 years ago
A purple rock as a mass of 316 grams and a density of 5.9 g/mL. Determine the volume of this rock in mL.
MakcuM [25]

Answer:

The answer is

<h2>53.56 mL</h2>

Explanation:

The volume of a substance when given the density and mass can be found by using the formula

volume =  \frac{mass}{density}  \\

From the question

mass of rock = 316 g

density = 5.9 g/mL

The volume of the rock is

volume =  \frac{316}{5.9}  \\  = 53.5593220...

We have the final answer as

<h3>53.56 mL</h3>

Hope this helps you

5 0
3 years ago
What is the enthalpy of reaction for the decomposition of calcium carbonate?
77julia77 [94]

Answer:

First Blank: 656.3 kJ

Second Blank: Endothermic

Explanation:

Edge 21'

4 0
3 years ago
Descibe the methods you will use to identify and isolate yeast and bacteria in a pineapple juice​
zalisa [80]

Answer:

The correct answer would be the use of differential and selective growth medium.

Explanation:

The mixed colonies states of certain species can be developed on the differential and specific media relying on the morphology saw in the general media. These types of selective and differential media will allow certain microorganisms to grow only and not all the rest species present on the media.

It will help in recognizing species present in the mixed colonies present in such a growth medium. Different tests like catalase can be performed to dispose of certain choices not long before the utilization of the differential and particular media.

Thus, the correct answer would be the use of differential and selective growth medium.

4 0
3 years ago
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