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2 years ago

Please help?

Mathematics

1 answer:

Sever21 [200]2 years ago

3 0

Answer:

88 feet per second

Step-by-step explanation:

quick maths

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True or false: the following graph demonstrates a proportional relationship between y and x. Explain.

MA_775_DIABLO [31]

Answer:

true cuz i say so

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

My Scando-Germanic friend, Odd Zahlen, often brings a die to class to answer multiple-choice final exam questions. Each multiple

Paraphin [41]

Answer:

$P(A=5)= 0.1366$

Step-by-step explanation:

From each multiple-choice question, there consists three answers to each;

So the probability of picking, the correct answer as they are uniformly distributed among the choices (a), (b), and (c) will be;

P(correct answer) = $\frac{1}{3}$

Now, to determine the probability of obtaining exactly 5 correct answers on a ten question examination using this method

Let use A as representative for the numbers of correct answers out of 10 questions that is being answered.

∴

$P(A=5)= [\left \ {{10} \atop {5}} \right.]$ $(\frac{1}{3}) ^5$ $(1-\frac{1}{3})^{10-5}$

$P(A=5)= [\left \ {{10} \atop {5}} \right.](\frac{1}{3}) ^5 (\frac{2}{3}) ^5$

$P(A=5)= 0.13657$

$P(A=5)= 0.1366$

4 0

4 years ago

I came up the answer as 57. I will attach my note, can you check?

ololo11 [35]

BC=19

Explanation

Step 1

ABE

triangle ABE is rigth triangle, then let

$\begin{gathered} Angle=60 \\ adjacentside=BE \\ opposit\text{ side(the one in front of the angle)= AB=}\frac{19\sqrt[]{6}}{4} \end{gathered}$

so, we need a function that relates, angle, adjancent side and opposite side

$\tan \theta=\frac{opposite\text{ side}}{\text{adjacent side}}$

replace

$\begin{gathered} \tan \theta=\frac{opposite\text{ side}}{\text{adjacent side}} \\ \tan 60=\frac{AB}{\text{BE}} \\ \text{cross multiply} \\ \text{BE}\cdot\tan \text{ 60=AB} \\ \text{divide both sides by tan 60} \\ \frac{\text{BE}\cdot\tan\text{ 60}}{\tan\text{ 60}}=\frac{\text{AB}}{\tan\text{ 60}} \\ BE=\frac{\text{AB}}{\tan\text{ 60}} \\ \text{if AB=}\frac{19\sqrt[]{6}}{4} \\ BE=\frac{\frac{19\sqrt[]{6}}{4}}{\sqrt[]{3}} \\ BE=\frac{19\sqrt[]{6}}{4\sqrt[]{3}} \end{gathered}$

Step 2

BED

again, we have a rigth triangle,then let

$\begin{gathered} \text{Hypotenuse}=BD \\ \text{adjacent side= BE=6.71} \\ \text{angle}=\text{ 45} \end{gathered}$

so, we need a function that relates; angle, hypotenuse and adjacent side

$\cos \theta=\frac{adjacent\text{ side}}{\text{hypotenuse}}$

replace.

$\begin{gathered} \cos \theta=\frac{adjacent\text{ side}}{\text{hypotenuse}} \\ \cos 45=\frac{6.71}{\text{BD}} \\ BD=\frac{6.71}{\cos \text{ 45}} \\ BD=\frac{\frac{19\sqrt[]{6}}{4\sqrt[]{3}}}{\frac{\sqrt[]{2}}{2}} \\ BD=\frac{38\sqrt[]{6}}{4\sqrt[]{6}} \\ BD=\frac{38}{4} \end{gathered}$

Step 3

finally BDE

let

angle=30

opposite side= BD

use sin function

$\begin{gathered} \sin \theta=\frac{opposite\text{ side}}{\text{hypotenuse}} \\ \text{replace} \\ \sin \text{ 30=}\frac{BD}{BC} \\ BC\cdot\sin 30=BD \\ BC=\frac{BD}{\sin \text{ 30}} \\ BC=\frac{\frac{38}{4}}{\frac{1}{2}} \\ BC=\frac{76}{4}=19 \\ BC=19 \end{gathered}$

so, the answer is 19

I hop