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gtnhenbr [62]
2 years ago
7

Please help?

Mathematics
1 answer:
Sever21 [200]2 years ago
3 0

Answer:

88 feet per second

Step-by-step explanation:

quick maths

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2 years ago
Please Help! 30 points! Real answers pls The box plot below shows the total amount of time, in minutes, the students of a class
padilas [110]

Hii!

So I did this and I have A!

A: You cannot get the mean from the graph but you CAN get the third quartile!

B: To find the interquartile range (IQR) we subtract the third and first quartiles:

60-35 = 25

C:  An outlier would be much larger than the rest of the data or much smaller than the rest of the data. An outlier would make the "whisker" portion longer and could potentially slightly shift the box.

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3 years ago
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Which is the area of a parallelogram with a base of 13 centimeters and a height of 3 centimeters?
GREYUIT [131]
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4 0
3 years ago
Given the functionf ( x ) = x^2 + 7 x + 10/ x^2 + 9 x + 20
vladimir1956 [14]

<em>x = -4 is a vertical asymptote for the function.</em>

<h2>Explanation:</h2>

The graph of y=f(x) is a vertical has an asymptote at x=a if at least one of the following statements is true:

1) \ \underset{x\rightarrow a^{-}}{lim}f(x)=\infty\\ \\ 2) \ \underset{x\rightarrow a^{-}}{lim}f(x)=-\infty \\ \\ 3) \ \underset{x\rightarrow a^{+}}{lim}f(x)=\infty \\ \\ 4) \ \underset{x\rightarrow a^{+}}{lim}f(x)=\infty

The function is:

f(x)=\frac{x^2+7x+10}{x^2+9x+20}

First of all, let't factor out:

f(x)=\frac{x^2+5x+2x+10}{x^2+5x+4x+20} \\ \\ f(x)=\frac{x(x+5)+2(x+5)}{x(x+5)+4(x+5)} \\ \\ f(x)=\frac{(x+5)(x+2)}{(x+5)(x+4)} \\ \\ f(x)=\frac{(x+2)}{(x+4)}, \ x\neq  5

From here:

\bullet \ When \ x \ approaches \ -4 \ on \ the \ right: \\ \\ \underset{x\rightarrow -4^{+}}{lim}\frac{(x+2)}{(x+4)}=? \\ \\ \underset{x\rightarrow -4^{+}}{lim}\frac{(-4^{+}+2)}{(-4^{+}+4)} \\ \\ \\ The \ numerator \ is \ negative \ and \ the \ denominator \\ is \ a \ small \ positive \ number. \ So: \\ \\ \underset{x\rightarrow -4^{+}}{lim}\frac{(x+2)}{(x+4)}=-\infty

\bullet \ When \ x \ approaches \ -4 \ on \ the \ left: \\ \\ \underset{x\rightarrow -4^{-}}{lim}\frac{(x+2)}{(x+4)}=? \\ \\ \underset{x\rightarrow -4^{-}}{lim}\frac{(-4^{-}+2)}{(-4^{-}+4)} \\ \\ \\ The \ numerator \ is \ a \ negative \ and \ the \ denominator \\ is \ a \ small \ negative \ number \ too. \ So: \\ \\ \underset{x\rightarrow -4^{-}}{lim}\frac{(x+2)}{(x+4)}=+\infty

Accordingly:

x=-4 \ is \ a \ vertical \ asymptote \ for \\ \\ f(x)=\frac{x^2+5x+2x+10}{x^2+5x+4x+20}

<h2>Learn more:</h2>

Vertical and horizontal asymptotes: brainly.com/question/10254973

#LearnWithBrainly

5 0
3 years ago
TIME REMAINING
alekssr [168]

The solution of the equations is (-2, -1)

<h3>System of equation:</h3>

2x - 3y = -1

11x  - 9y = -13

Using elimination method let multiply the first equation by -3.

Therefore,

-6x + 9y = 3

11x - 9y = -13

5x = -10

x = -10 / 5

x = -2

let's find y as follows;

2(-2) - 3y = -1

-4 - 3y = -1

-3y = -1 + 4

-3y = 3

y = 3 / -3

y = -1

learn more on system of equation here: brainly.com/question/1451150

6 0
2 years ago
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