yikes i remember doing this but.... i completely forgot ;–; i really wish i could help
Hii!
So I did this and I have A!
A: You cannot get the mean from the graph but you CAN get the third quartile!
B: To find the interquartile range (IQR) we subtract the third and first quartiles:
60-35 = 25
C: An outlier would be much larger than the rest of the data or much smaller than the rest of the data. An outlier would make the "whisker" portion longer and could potentially slightly shift the box.
He ANWSER I got would be c idk if this is right or not I honk it might be
<em>x = -4 is a vertical asymptote for the function.</em>
<h2>
Explanation:</h2>
The graph of
is a vertical has an asymptote at
if at least one of the following statements is true:

The function is:

First of all, let't factor out:

From here:


Accordingly:

<h2>Learn more:</h2>
Vertical and horizontal asymptotes: brainly.com/question/10254973
#LearnWithBrainly
The solution of the equations is (-2, -1)
<h3>System of equation:</h3>
2x - 3y = -1
11x - 9y = -13
Using elimination method let multiply the first equation by -3.
Therefore,
-6x + 9y = 3
11x - 9y = -13
5x = -10
x = -10 / 5
x = -2
let's find y as follows;
2(-2) - 3y = -1
-4 - 3y = -1
-3y = -1 + 4
-3y = 3
y = 3 / -3
y = -1
learn more on system of equation here: brainly.com/question/1451150