The degree of freedom for t statistic is 11.
According to the given question.
For a repeated-measure study, comparing two treatments with 12 scores in each treatment .
So, we can say that sample size, n = 12.
We know that, when you have a sample and estimate the mean, we have
n – 1 degrees of freedom, where n is the sample size.
Therefore,
The degree of freedom for the given sample test will be
d.f = n -1
⇒ d.f = 12 - 1
⇒ d.f = 11
Hence, the degree of freedom for t statistic is 11.
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Answer:
21 24 9
6 18 30
27 12 15
Step-by-step explanation:
Kory and Leanne will meet each other again after 36 minutes from starting i.e. at 10:36 am .
<u>Step-by-step explanation:</u>
Here we have , Leanne runs a lap in 12 minutes. Kory runs a lap in 9 minutes. We need to find out that If they both start running at 10 am, at what time will they both cross the start together again . Let's find out:
Kory runs a lap in 9 minutes and , Leanne in 12 minutes , in order to find at what time will they both cross the start together again we will find LCM of 9 & 12 :
⇒ 
⇒ 
So ,LCM of 9 & 12 is 36 .That means Kory and Leanne will meet each other again after 36 minutes from starting i.e. at 10:36 am .
In clear way , Kory will run race as :
1st lap = 9 minutes
2nd lap = 18 minutes
3rd lap = 27 minutes
4th lap = 36 minutes , i.e. at 10:36 am he'll complete his 4th lap
For , Leanne
1st lap = 12 minutes
2nd lap = 24 minutes
3rd lap = 36 minutes i.e. at 10:36 am he'll complete his 3rd lap .
This means Kory & Leanne will meet at 10:36 am completing there 4th and 3rd lap respectively .
All u need to do is 3 x 3x 4 / 2= 18ft
Add up the lunch and belt.
5.47+8.95
14.42
Now subtract that from the money Jane had at first.
23-14.42
8.58
So B. Jane has spent $8.58 on the necklace.