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Korvikt [17]
4 years ago
11

Solve the quadratic equation: 2x2 + 11x − 6 = 0

Mathematics
1 answer:
Ostrovityanka [42]4 years ago
3 0

Answer:

see explanation

Step-by-step explanation:

To factorise the quadratic consider the factors of the product of the coefficient of the x² term and the constant term which sum to give the coefficient of the x term.

product = 2 × - 6 = - 12 and sum = + 11

The factors are + 12 and - 1

Use these factors to split the middle term

2x² + 12x - x - 6 = 0 ( factor the first/second and third/fourth terms )

2x(x + 6) - 1(x + 6) = 0 (factor out (x + 6) )

(x + 6)(2x - 1) = 0

equate each factor to zero and solve for x

x + 6 = 0 ⇒ x = - 6

2x - 1 = 0 ⇒ x = \frac{1}{2}


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emmainna [20.7K]

Answer:

I found two different solutions. Hope one of them help!

1. x = -1/3 = -0.333

2. x = 5/2 = 2.500

Step-by-step explanation:

13 ± √ 289

  x  =    ——————

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Can  √ 289 be simplified ?

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To be able to remove something from under the radical, there have to be  2  instances of it (because we are taking a square i.e. second root).

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So now we are looking at:

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Two real solutions:

x =(13+√289)/12=(13+17)/12= 2.500

or

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x = -1/3 = -0.333

x = 5/2 = 2.500

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