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3 years ago

7

At princess lake there are 100 ducks. if the number of ducks at the lake doubles every 6 months, how many ducks will there be in

2 years?

2 answers:

arsen [322]3 years ago

4 0

I guess 1600
i hope that's true

Andrew [12]3 years ago

3 0

The answer is 1600

plz thank me, it motivates me to keep answering your questions :)

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A certain radioactive isotope has leaked into a small stream. Three hundred days after the leak, 3% of the original amount of t

sesenic [268]

If the half-life is t, then every t days, the amount of the radioactive isotope will be cut in half.
(1/2)^(number of half-lives) = 3%
number of half-lives = ln(0.03) / ln(0.5)
This gives the number of half-lives as 5.06.
Then 300 days = (5.06)(length of 1 half-life)
length of 1 half-life = 300 / 5.06 = 59.29 days

6 0

3 years ago

3/2a - ab + 1 (if a = 5/6 and b = 3/10)

dedylja [7]

The answer is 2.

3/2a - ab + 1
3/2(5/6) - 5/6(3/10) + 1
5/4 - 1/4 + 1
4/4 + 1
1 + 1 = 2

7 0

1 year ago

PLEASE HELP ME!!! 10 points!

Brut [27]

Answer:

5/4

hope it helps u

3 0

2 years ago

Read 2 more answers

Karen could lift 18 pounds with a

Grace [21]

Answer:

14 more pounds

Step-by-step explanation:

32-18

5 0

3 years ago

Read 2 more answers

Let f(x) = |x| for all real numbers x. Write the formula for the function represented by the described

Ostrovityanka [42]

Answer:

$y=(\frac{1}{3}f(x-3))-1$

Step-by-step explanation:

Please see the picture below.

1. Given the function f(x) = |x|, applying a vertical stretch with scale factor $\frac{1}{3}$ , we have the transformed function:

$y=\frac{1}{3}f(x)$

2. Applying a translation of 3 units to the right, we have:

$y=\frac{1}{3}f(x-3)$

3. Finally applying a translation down of 1 unit, we have:

$y=(\frac{1}{3}f(x-3))-1$

6 0

3 years ago