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Rina8888 [55]
3 years ago
15

Estimate 1.75 * 12.5

Mathematics
2 answers:
NeX [460]3 years ago
7 0

Answer:

21.875, round as needed.

Step-by-step explanation:

1.75 * 12.5

21.875

You can also round to:

21.88

21.9

22

Just depends on what your teacher is asking

tiny-mole [99]3 years ago
7 0

Answer:

2 * 13 = 26

Step-by-step explanation:

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There is a rectangular Prism with a Length of 12, a Width of 20, and a Height of 16. Someone says the Surface Area is 3,840. Are
SOVA2 [1]

Answer:

INCORRECT

Step-by-step explanation:

Given a rectangular prism,

Total Surface Area = 2(LW+LH+WH)

If Length = 12, Width =20, and;  Height = 16.

Total Surface Area = 2(12*20+12*16+20*16)

=2(240+192+320)

=2(752)

=1504

The Surface Area is 1504 Square Units, therefore if someone says the surface Area is 3,840, they are incorrect!

7 0
3 years ago
Use the following vectors to answer parts​ (a) and​ (b). v1equals=[Start 3 By 1 Matrix 1st Row 1st Column 1 2nd Row 1st Column n
erik [133]

Answer:

(1) No matter what's the value of h, \vec{v}_3 is never in the span of \vec{v}_1 and \vec{v}_2.

(2) The three vectors \vec{v}_1, \vec{v}_2, and \vec{v}_3 are always linearly dependent for all real h.

Step-by-step explanation:

<h3>(a)</h3>

If \vec{v}_3 is in the span of \vec{v}_1 and \vec{v}_2, there need to exist real a and b such that

a\; \vec{v}_1 + b\; \vec{v}_2 = \vec{v}_3.

Assume that such a and b do exist.

In other words,

\displaystyle a \left[\begin{array}{c}{1 \\ -4\\2} \end{array}\right] + b\left[\begin{array}{c}{-4 \\ 16\\-8}\end{array}\right] = \left[\begin{array}{c}5 \\7 \\ h\end{array}\right].

\displaystyle \left[\begin{array}{c}{a \\ -4a\\2a} \end{array}\right] + \left[\begin{array}{c}{-4b \\ 16b\\-8b}\end{array}\right] = \left[\begin{array}{c}5 \\7 \\ h\end{array}\right].

\left\{\begin{array}{rrcr} a & - 4b &=& 5\\ -4a & + 16b &= &7\\2a & -8b & =&h\end{aligned}\right..

Rewrite as an augmented matrix and row-reduce:

\displaystyle \left[ \begin{array}{cc|c} 1 & -4 & 5 \\ -4 & 16 & 7 \\ 2 & -8 & h\end{array}\right].

(Add four times row one to row two and -2 times row one to row three.)

\displaystyle \sim \left[ \begin{array}{cc|c} 1 & -4 & 5 \\ 0 & 0 & 27 \\ 0 & 0 & h - 10\end{array}\right].

Note that in row two,

  • Left-hand side: 0;
  • Right-hand side: 27\neq 0.

In other words, this system is inconsistent. There's no real a and b that would satisfy the condition

a\; \vec{v}_1 + b\; \vec{v}_2 = \vec{v}_3.

Hence \forall h \in \mathbb{R}, \quad \vec{v}_3\not \in \text{Span}\{\vec{v}_1, \vec{v}_2\}.

There's no real h that allows h, \vec{v}_3 to be part of the span of \vec{v}_1 and \vec{v}_2.

<h3>(b)</h3>

If the three vectors are linearly dependent, at least one of them can be expressed as the linear combination of the other two.

Note that

\vec{v}_2 = (-4)\vec{v}_1 + 0 \; \vec{v}_3. In other words, \vec{v}_2 can be written as the linear combination of the other two vectors. Additionally, since the coefficient in front of \vec{v}_3 is zero, neither the exact value of \vec{v}_3 nor the value of h will make a difference. Therefore, for all h \in \mathbb{R}, the three vectors \vec{v}_1, \vec{v}_2, and \vec{v}_3 are linearly dependent.

8 0
3 years ago
Consider the equation below and determine the value of k
Ksenya-84 [330]

Answer:

k=9

hope my answer above helps

6 0
3 years ago
ESTIMATE FOR 85.1 divided by 23
Korvikt [17]

Answer:

3.7 is your answer or 4.0 or 4


Step-by-step explanation:


6 0
3 years ago
What is the Percentage area of 2.6 standard deviation
zvonat [6]
Please try to be more specific.  What I think you meant was "what is the area under the standard normal curve to the left of 2.6 standard deviations above the mean?"  If that's it, the area can be found from a table of z-scores (look for z=2.6) or by using a calculator:

normalcdf(-100,2.6) = 0.995.
6 0
3 years ago
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