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Sidana [21]
4 years ago
13

(BRAINLIEST QUESTION) What are some challenges that will need to be overcome in order for the Internet of Vehicles to become a r

eality?
Computers and Technology
1 answer:
SVEN [57.7K]4 years ago
5 0

Answer:

Internet of Vehicles (IoV) is a concept in intelligent transportation systems (ITS) in which vehicles with IoV will be able to communicate with each other and [ublic networks through V2I (vehicle-to-infrastructure), V2P (vehicle-to-pedestrian) interaction, and V2V (vehicle-to-vehicle).

There are some challenges that will need to be overcome in order for the Internet of Vehicles to become a reality:

  • IoV is unable to predict human behavior and body language of other drivers so it can be dangerous sometimes to take respective actions that a normal vehicle driver can do.
  • Risk of security challenges and security attacks is one of the biggest challenges as the networks can be manipulated.
  • People have lack of trust in IoV due to privacy and health concern.
  • The initial cost of IoV is very high that only few rich people can buy it.
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Which soft skill involves the ability to work harmoniously with your colleagues and improve productivity?
Lina20 [59]
B.Teamwork is a soft skill involves the ability to work harmoniously with your colleagues and improve productivity. It is the collaborative effort of a team to complete a task or to achieve a common goal in the most effective and efficient way.  

 


4 0
3 years ago
A bowl contains 20 candies; 15 are chocolate and 5 are vanilla. You select 5 at random. What is the probability that all 5 are c
Sindrei [870]

Answer: 0.1937

Explanation:

Given : A bowl contains 20 candies; 15 are chocolate and 5 are vanilla.

If we select 5 candies, then the number of ways to select them is given by permutations.

The number of ways to select 5 candies is given by :-

^{15}P_5=\dfrac{15!}{(15-5)!}=\dfrac{15\times14\times13\times12\times11\times10!}{10!}=360360

The number of ways of selecting any 5 candies out of 20:-

^{20}P_5=\dfrac{20!}{(20-5)!}\\\\=\dfrac{20\times19\times18\times17\times16\times15!}{15!}\\\\=1860480

Now, the probability that all 5 are chocolate :-

=\dfrac{360360}{1860480}=0.193691950464\approx0.1937

Hence, the probability that all 5 are chocolate =0.1937

5 0
3 years ago
Read 2 more answers
Smith wants to get a job in network systems. Which major should he choose to give him the best chance of getting a job?
Sever21 [200]
<span>computer engineering</span>
5 0
4 years ago
Read 2 more answers
Identify a syntax used to create a spinner control using an input element. a. b. c. d.
Lorico [155]

Answer:

Option A:

<input name="name" id="id" type="number" value="value" step="value" min="value" max="value" />

Explanation:

Spinner control is a graphical control element where user can adjust the value by pressing up or down arrow button. An example is given in the attached image.

In HTML, one of the key attributes we must use to create a spinner control is "step". The attribute "step" is required to specify the interval of the step value when user press the up or down arrow button.

If we set the attribute values as follows:

  • type = "number"
  • value = 2
  • min = 0
  • max = 10

The setting above will give a spinner control with a range of legal numbers between 0, 2, 4, 6, 8 and 10.

6 0
3 years ago
An array of integers named parkingTickets has been declared and initialized to the number of parking tickets given out by the ci
Sedaia [141]

Answer:

Following code will store the largest value in array parkingTickets in the variable mostTickets

mostTickets = parkingTickets[0];

for(int k = 0; k<parkingTickets.length; k++)

{

if(parkingTickets[i]>mostTickets)

{

 mostTickets = parkingTickets[i];

}

}

Explanation:

In the above code segment, initially the number of tickets at first index is assumed as largest value of tickets in array.

Then using a for loop each value in the array parkingTickets is compared with the current mostTickets value.

If the compared value in parkingTickets array is larger than the current mostTickets value. Then that value is assigned to mostTickets.

This process is repeated for all elements in array.

Thus after looping through each element of array the largest value in array will get stored in mostTickets variable.  

6 0
3 years ago
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