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gavmur [86]
3 years ago
5

In 1950, there were 40.3 million cars registered in the United States. In 1990, there were 133.7 million cars registered in the

United States. What was the percent increase of registered cars from 1950 to 1990?
Mathematics
1 answer:
Sophie [7]3 years ago
7 0
\frac{133.7}{40.3}*100\%\approx331,76\%
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Someone please help!
DochEvi [55]

Answer: 62cm^2

Step-by-step explanation: 70-8=62

7 0
3 years ago
Penny received an unexpected $5,000.00 gift from a distant relative. She invests it in a mutual fund that increases the value of
dusya [7]

Answer:

Penny would need to put in ~ $18,181.82

Step-by-step explanation:

Using the equation A = P(1+rt)

Where A = the total

P is equal to the starting amount

r is equal to the rate (percent)

and t is equal to the total time.

We can put in:

A = $40,000

r = 0.08 (8%)

t = 15

40,000 = P(1 +(0.08* 15))\\40,000 = P(1+1.2)\\40,000 = P(2.2)\\\frac{40,000}{2.2} = P\\ \frac{200,000}{11} = P\\P = $18181.8181818181...

Round to the nearest whole cent

P = $18,181.82

3 0
3 years ago
Ellen Newman has an income of $18,150 and claims 5 exemptions. The amount allowed for each exemption is $1,000. Her state tax is
Vanyuwa [196]
State tax is computed by first subtracting the amount of exemptions (5*$1000=$5000) from annual income and then multiplying it by the state tax.

($18150-$5000)*5%= $657.50
3 0
3 years ago
How many hours did Diana work of she was paid $45.50
JulijaS [17]
I think it would be C because the equation is y=7x. y=7x is also equal to x=1/7y. If y=45.50, then you would have to divide y by 7, which would equal 6.5.
8 0
3 years ago
Read 2 more answers
WHAT IS THE REMAINDER WHEN <img src="https://tex.z-dn.net/?f=32%5E%7B37%5E%7B32%7D%20%7D" id="TexFormula1" title="32^{37^{32} }"
Feliz [49]

Recall Euler's theorem: if \gcd(a,n) = 1, then

a^{\phi(n)} \equiv 1 \pmod n

where \phi is Euler's totient function.

We have \gcd(9,32) = 1 - in fact, \gcd(9,32^k)=1 for any k\in\Bbb N since 9=3^2 and 32=2^5 share no common divisors - as well as \phi(9) = 6.

Now,

37^{32} = (1 + 36)^{32} \\\\ ~~~~~~~~ = 1 + 36c_1 + 36^2c_2 + 36^3c_3+\cdots+36^{32}c_{32} \\\\ ~~~~~~~~ = 1 + 6 \left(6c_1 + 6^3c_2 + 6^5c_3 + \cdots + 6^{63}c_{32}\right) \\\\ \implies 32^{37^{32}} = 32^{1 + 6(\cdots)} =  32\cdot\left(32^{(\cdots)}\right)^6

where the c_i are positive integer coefficients from the binomial expansion. By Euler's theorem,

\left(32^{(\cdots)\right)^6 \equiv 1 \pmod9

so that

32^{37^{32}} \equiv 32\cdot1 \equiv \boxed{5} \pmod9

7 0
2 years ago
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