If you observe the two given equations, the left hand side of both equation is the same and is equal to y.
Since the left hand side of two equations is the same, we can conclude that the right hand side of two equations must also be the same.
So, setting them right hand sides of both equations equal to each other and solving for x, we can find the solution to the simultaneous equations.
Therefore, the correct answer is option B
Answer:
6
Step-by-step explanation:
I'm 99% sure you know the answer to this and didn't have to resort to this website.
3-5 = -2
Subtracting negative numbers means it becomes positive.
So the gist is that your adding 4 and 2 which is 6.
I think the first one is ( C :3 ) and the other one is B 2
The coefficient matrix is build with its rows representing each equation, and its columns representing each variable.
So, you may write the matrix as
![\left[\begin{array}{cc}\text{x-coefficient, 1st equation}&\text{y-coefficient, 1st equation}\\\text{x-coefficient, 2nd equation}&\text{y-coefficient, 2nd equation} \end{array}\right]](https://tex.z-dn.net/?f=%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D%5Ctext%7Bx-coefficient%2C%201st%20equation%7D%26%5Ctext%7By-coefficient%2C%201st%20equation%7D%5C%5C%5Ctext%7Bx-coefficient%2C%202nd%20equation%7D%26%5Ctext%7By-coefficient%2C%202nd%20equation%7D%20%5Cend%7Barray%7D%5Cright%5D%20%20)
which means
![\left[\begin{array}{cc}4&-3\\8&-3\end{array}\right]](https://tex.z-dn.net/?f=%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D4%26-3%5C%5C8%26-3%5Cend%7Barray%7D%5Cright%5D%20%20)
The determinant is computed subtracting diagonals:
![\left | \left[ \begin{array}{cc}a&b\\c&d\end{array}\right]\right | = ad-bc](https://tex.z-dn.net/?f=%20%5Cleft%20%7C%20%5Cleft%5B%20%5Cbegin%7Barray%7D%7Bcc%7Da%26b%5C%5Cc%26d%5Cend%7Barray%7D%5Cright%5D%5Cright%20%7C%20%3D%20ad-bc%20)
So, we have
![\left | \left[\begin{array}{cc}4&-3\\8&-3\end{array}\right] \right | = 4(-3) - 8(-3) = -4(-3) = 12](https://tex.z-dn.net/?f=%20%5Cleft%20%7C%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D4%26-3%5C%5C8%26-3%5Cend%7Barray%7D%5Cright%5D%20%5Cright%20%7C%20%3D%204%28-3%29%20-%208%28-3%29%20%3D%20-4%28-3%29%20%3D%2012%20%20)
Answer: 336.14 cm²
Step-by-step explanation:
To find the area of the rectangle after being cut, we want to find the area of the two semicircles and subtract it from the area of the rectangle. The area of the rectangle is just base times height, or 35cm times 14cm = 490cm² . Since there are two semicircles with the same diameter, we can just solve for the area of a circle and subtract it. To find the area of the circle, we need the radius, which we get by dividing the diameter by 2. After that, we calculate the radius to be 7cm, squared and multiplied by 3.14 (area of a circle) to get 153.86 cm². Subtract the areas, and we get 490 - 153.86 = 336.14 cm²
