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Naddik [55]
2 years ago
11

11x - 8y = 3 in slope intercept form

Mathematics
1 answer:
SashulF [63]2 years ago
5 0
Najeejushshehhebdbsbehhebeshhejebehebsvsbsbsbs

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If a sprinkler waters 1/15 of a lawn in 1/5 of an hour, how much time will it take to water the entire lawn?
GaryK [48]

Answer:

3 hours

Step-by-step explanation:

To solve this we can first find out how many minutes is 1/5th of an hour which is: 12 mins.

Now we know it will take 15 sets of 12 minutes to water the full lawn so we can multiply 15*12 to get our answer.

15*12 = 180

Now we divide 180 (minutes) by 60 (minutes) to find out how many hours that is:

180/60 = 3 hours

Hope this helped! If possible please leave a thanks so I can continue to help out others :),

comment if you have any questions.

5 0
3 years ago
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BRAINLIEST FOR FIRST ANSWER!!!! The right rectangular prism will be sliced parallel to its base along the dashed line.
stepan [7]
Rectangle and the area is 8 
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3 years ago
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.. Stevie had of a gallon of paint. He divided the paint equally into three containers. How much paint did he put in each contai
bekas [8.4K]
2.2 pints because 1 gallon is equal to 8 pints so then you divide 8 by 3 because their is 3 containers.
5 0
2 years ago
Helppoo 10 points! I’ll mark brainliest!
77julia77 [94]

Answer Yes, because you take the answer from 100+45 and subtract 3 to get to 97 and then you add 29 to make the 47 a 74.

Step-by-step explanation:

4 0
3 years ago
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Keegan leans an 18-foot ladder against the top of a wall. The bottom of the ladder is 4.5 feet from the base of the wall. What i
zaharov [31]

Answer: C. 17.5 feet

Step-by-step explanation:

The attached photo shows the triangle ABC formed by the ladder and the wall. It is a right angle triangle because one of its angles is 90 degrees. The ladder is the hypotenuse of the triangle. To determine the height of the wall, we would find BC by applying Pythagoras theorem

Hypotenuse^2 = opposite ^2 + adjacent^2

18^2 + 4.5^2 + BC^2

BC^2 = 324 - 20.25 = 303.75

BC = √303.75 = 17.5 feet.

3 0
3 years ago
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