Answer:
The speed in of the plane is 115.47 m/sec
Step-by-step explanation:
Given:
Height at which the plane is flying = 6000 m
Angle of elevation at the radar base = 30 Degrees
Angle of elevation at the radar base after one minute = 60 Degrees
To Find:
The Speed of the plane in meter per second = ?
Solution:
Let us use the tangent of the angle to find the distance (d) to a point directly below plane:
<u>when the angle is 30 degrees</u>



d1 = 10392.3 meters
<u>when the angle is 60 degrees</u>



d2 = 3464.1 meters
<u>distance travelled by aircraft in 1 min is </u>
=>d1 - d2
=>0392.3 - 3464.1
= 6928.2 m/min
<u>Now converting to m/sec</u>
=>
=>115.47 m/sec
Answer:
hope this helps
Step-by-step explanation:
For a.) I would do the simplist example possible and make all 3 angles equal. So you would divide 180° degrees by 3. This gives you 60° for each angle. That is still acute.
b.) complementary angles mean they add up to 90°
If one has to be greater than 45° you can so 68° and 22°.
c.) 100 - 10,10; 20,5; 50,2; 4,25
You can choose any pair for the length and width of the ones I put above. :)
d.) angle ABC can equal 32° and angle CBD can be 10°
Answer:
c Po ung ans :))))))))))))))))))
Answer: root t(5)/19300
Explanation:
P(t) = 19300(5)^t
P-1(t) = root t(5)/19300