Please answer this correctly

Will a large-sample confidence interval be valid if the population from which the sample is taken is not normally distributed? e

Dovator [93]

A normal distribution is a type of continuous probability distribution for a real-valued random variable in statistics.

Yes, the large-sample confidence interval will be valid.

<h3>What is meant by normal distribution?</h3>

A normal distribution is a type of continuous probability distribution for a real-valued random variable in statistics.

The normal distribution, also known as the Gaussian distribution, is a symmetric probability distribution about the mean, indicating that data near the mean occur more frequently than data far from the mean.

The confidence interval will be valid regardless of the shape of the population distribution as long as the sample is large enough to satisfy the central limit theorem.

<h3>What does a large sample confidence interval for a population mean?</h3>

A sample is considered large when n ≥ 30.

By 'valid', it means that the confidence interval procedure has a 95% chance of producing an interval that contains the population parameter.

To learn more about normal distribution, refer to:

brainly.com/question/23418254

#SPJ4

8 0

1 year ago

Subtract 7 from 16 and then multiply by 4 which expression shows this calculation

Masteriza [31]

Answer:

7 - 16 = 9 x 4 = 36

Step-by-step explanation: 1 - 16 7 times. 9 + 9 + 9 + 9 = 36

5 0

3 years ago

Trapezoids and kites

lisov135 [29]

QUESTION 3

The sum of the interior angles of a kite is $360\degree$ .

$\Rightarrow 36\degree +70\degree+m$ .

$\Rightarrow 106\degree+m$ .

$\Rightarrow m$ .

But the two remaining opposite angles of the kite are congruent.

$\Rightarrow m$

$\Rightarrow m$ .

$\Rightarrow 2m$ .

$\Rightarrow m$ .

QUESTION 4

RH is the hypotenuse of the right triangle formed by the triangle with side lengths, RH,12, and 20.

Using the Pythagoras Theorem, we obtain;

$|RH|^2=12^2+20^2$

$|RH|^2=144+400$

$|RH|^2=544$

$|RH|=\sqrt{544}$

$|RH|=4\sqrt{34}$

QUESTION 5

The given figure is an isosceles trapezium.

The base angles of an isosceles trapezium are equal.

Therefore $m$

QUESTION 6

The measure of angle Y and Z are supplementary angles.

The two angles form a pair of co-interior angles of the trapezium.

This implies that;

$m$

$\Rightarrow m$

QUESTION 7

The sum of the interior angles of a kite is $360\degree$ .

$\Rightarrow 48\degree +110\degree+m$ .

$\Rightarrow 158\degree+m$ .

$\Rightarrow m$ .

But the two remaining opposite angles are congruent.

$\Rightarrow m$

$\Rightarrow m$ .

$\Rightarrow 2m$ .

$\Rightarrow m$ .

QUESTION 8

The diagonals of the kite meet at right angles.

The length of BC can also be found using Pythagoras Theorem;

$|BC|^2=4^2+7^2$

$\Rightarrow |BC|^2=16+49$

$\Rightarrow |BC|^2=65$

$\Rightarrow |BC|=\sqrt{65}$

QUESTION 9.

The sum of the interior angles of a trapezium is $360\degree$ .

$\Rightarrow m$ .

But the measure of angle M and K are congruent.

$\Rightarrow m$ .

6 0

3 years ago

Help me solve this problem please

Anton [14]

Answer:

y=-5x thats it so ype it in ir whatevet

4 0

3 years ago

Read 2 more answers

A group of artists is selling small prints to raise money for charity. They sell p prints, and make a profit of f(p) on the sale

liraira [26]

The correct answer is is D) If the group sells 15 prints they will loose $85.

To figure out which statement is true, we have to evaluate the function ,

$p(x)=17x-340$ for all the values given in options (A)-(D). A negative output represents a loss and a positive output will represent a profit.

In A $p=12$ so $f(12)=17\times 12-340=-136$ . In this case we gather that if they sell 12 prints, they will make a loss of $136. This tells us that option A is wrong.

In B, $p=28$ so $f(28)=17\times 28-340=136$ . In this case we gather that if they sell 28 prints, they make a profit of $136. This tells us that option B is wrong.

In C, $p=35$ so $f(35)=17\times 35-340=225$ . In this case we gather that if they sell 35 prints, they make a profit of $225. This tells us that option C is wrong.

Lastly, $p=15$ so $f(15)=17\times 15-340=-85$ . In this case we gather that if they sell 28 prints, they make a loss of 85 dollars. From this we gather that D is the correct option.

5 0

3 years ago