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weeeeeb [17]
3 years ago
12

Solve for s 2* s= 1.2 what is it​

Mathematics
2 answers:
Bond [772]3 years ago
4 0

Answer:

s=.6

Step-by-step explanation:

s=1.2/2

zepelin [54]3 years ago
4 0

Answer:

1.2

Step-by-step explanation:

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Combina los términos semejantes<br> -16 + 8x +20x -5y
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Find a general solution of y" + 4y = 0.
klio [65]

Answer:

y(x)=C_{1}cos2x+C_{2}sin(2x)

Step-by-step explanation:

It is a linear homogeneous differential equation with constant coefficients:

y" + 4y = 0

Its characteristic equation:

r^2+4=0

r1=2i

r2=-2i

We use these roots in order to find the general solution:

y(x)=C_{1}cos2x+C_{2}sin(2x)

8 0
3 years ago
Yesenia buys water to make tea for all her friends. She buys 1 qurt of water and 1/2 gallon of water. How many cups of water doe
Lina20 [59]

Answer:

12 cups of water

Step-by-step explanation:

This question has to do with conversion

We are told that she buy 1 quart and 1/2 gallon of water.

Hence,

1 quart of water = 4 cups of water

1 gallon of water = 16 cups of water

1/2 gallon of water = x

Cross Multiple

x = 1/2 × 16 cups of water

x = 8 cups of water.

Therefore, the total cups of water that she bought = 4 cups of water + 8 cups of water = 12 cups of water

6 0
3 years ago
What are the coordinates of the orthocenter of △JKL with vertices at J(−4, −1) , K(−4, 8) , and L(2, 8) ?
Sati [7]

<u>Answer-</u>

<em>The coordinates of the orthocenter of △JKL is (-4, 8)</em>

<u>Solution-</u>

The orthocenter is the point where all three altitudes of the triangle intersect. An altitude is a line which passes through a vertex of the triangle and is perpendicular to the opposite side.

For a right angle triangle, the vertex at the right angle is the orthocentre of the triangle.

Here we are given the three vertices of the triangle are  J(-4,-1), K(-4,8) and L(2,8)

If the triangle JKL satisfies Pythagoras Theorem, then triangle JKL will be a right angle triangle.

Applying distance formula we get,

JK^2= (-4+4)^2+ (8+1)^2=0+81=81\\\\KL^2= (-4-2)^2+ (8-8)^2=36+0=36\\\\JL^2= (-4-2)^2+(8+1)^2=36+81=117

As,

\Rightarrow 117=81+36

\Rightarrow JL^2=JK^2+KL^2

\Rightarrow \text{JKL is a right angle triangle}

\Rightarrow \angle K=90^{\circ}

Therefore, the vertex at K (-4, 8) is the orthocentre.

3 0
3 years ago
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