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Lunna [17]
3 years ago
8

Which is a function?!

Mathematics
1 answer:
a_sh-v [17]3 years ago
4 0

Answer:

c

Step-by-step explanation:

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A company with a fleet of 150 cars found that the emissions systems of only 4 out of the 25 they tested failed to meet pollution
salantis [7]

Answer:

No, there is no strong evidence that the percentage of the fleet out of compliance is different from their initial thought.

Step-by-step explanation:

We are given that a company with a fleet of 150 cars found that the emissions systems of only 4 out of the 25 they tested failed to meet pollution control guidelines.

The company initially believed that 30% of the fleet was out of compliance.

<u><em>Let p = percentage of the fleet that was out of compliance.</em></u>

SO, Null Hypothesis, H_0 : p = 30%   {means that the percentage of the fleet out of compliance is same as their initial thought}

Alternate Hypothesis, H_A : p \neq 30%   {means that the percentage of the fleet out of compliance is different from their initial thought}

The test statistics that will be used here is <u>One-sample z proportion</u> <u>statistics</u>;

                                 T.S.  = \frac{\hat p-p}{{\sqrt{\frac{\hat p(1-\hat p)}{n} } } } }  ~ N(0,1)

where, \hat p = percentage of the fleet out of compliance = \frac{4}{25} = 16%

           n = sample of systems tested = 25

So, <u><em>test statistics</em></u>  =  \frac{0.16-0.30}{{\sqrt{\frac{0.16(1-0.16)}{25} } } } }

                              =  -1.909

The value of the test statistics is -1.909.

<em>Since in the question we are not given with the level of significance at which hypothesis can be tested, so we assume it to be 5%. Now at 5% significance level, </em><u><em>the z table gives critical values between -1.96 and 1.96 for two-tailed test.</em></u><em> </em>

<em>Since our test statistics lies within the range of critical values of z, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which we fail to reject our null hypothesis.</em>

Therefore, we conclude that the percentage of the fleet out of compliance is same as their initial thought.

3 0
3 years ago
Calculus Help!
snow_lady [41]

Answer:

Yes.

Step-by-step explanation:

You would have to use L'Hopital's Rule. Infinity/Infinity is undefined, just like 0/0 is undefined.

I just googled this.

Before trying other techniques, plug in the arrow number. If the result is:

   A number, you’re done.

    A number over zero or infinity over zero, the answer is infinity.

    A number over infinity, the answer is zero.

    0/0 or ∞/∞, use L’Hôpital’s Rule.

The thing is, when you say you got your limit, do you mean\lim_{n \to \infty} (n+1)/n ?

This can just be found out by dividing by highest denominator power on numerator and denominator..

\lim_{n \to \infty} 1 + 1/n

the limit of 1 is 1.

the limit of 1/x is 0.

because its equal to one it diverges.

3 0
3 years ago
7) 11r - 12r
Alexeev081 [22]

7. -r

8. 11v

9. -19x

10. 6p

11. 16n

12. -4n -5

13. 15r

14. 9n + 1

8 0
3 years ago
If anyone wants to do these, here you go! P.S. I already did these and the first person to get them all correct gets a brainiest
marshall27 [118]

Answer:

5. 1/9? 6. -22? 7. -2? 8. -15? 9. -5? 10. 5?

6 0
3 years ago
Line segment NY has endpoints N(-11,5) and Y(5,-7). What is the equation of the perpendicular bisector of line NY?
Fiesta28 [93]
The first thing to do is find the slope of the given line m = (y2-y1)/(x2-x1). We need to find the slope because it is required to find the slope of the perpendicular line.

m = (-7-5)/(5+11) = -12/16 = -3/4

Now we find the midpoint of the line, this is where the perpendicular bisector be. Using the Midpoint equation

M=((x1+x2)/2,(y1+y2)/2)
M=((-11+5)/2, (5-7)/2)
M=(-6/2, -2/2)
M=(-3,-1)

Now that we have the slope and midpoint we can find the perpendicular bisector. A line is perpendicular to another if, when you multiply their slopes together they equal -1. To do this we simply invert the numerator and denominator of our current slope and flip the sign from negative to positive.

So, -3/4 becomes positive 4/3 for our new line. So for our perpendicular line we now know two things, the slope and a point on it (the bisector point). To find the equation of the line we need to plug the known point and slope into the equation y = mx + b and solve for b.

-1 = 4/3(-3) + b
-1 = -4 + b
b = -1 + 4
b = 3

Now we can build our equation for our perpendicular line

y = 4/3x + 3


4 0
3 years ago
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