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11111nata11111 [884]
3 years ago
11

A deli sells sliced meat and cheese. One customer purchases 4 pounds of meat and 5 pounds of cheese for a total of $30.50. A san

dwich shop owner comes in and purchases 11 pounds of meat and 14 pounds of cheese for $84.50. The system of equations below represents the situation.
4x + 5y = 30.50

11x + 14y = 84.50

The variable x represents the
.

The variable y represents the
.

The deli charges $
Mathematics
1 answer:
eimsori [14]3 years ago
5 0

Answer:

The cost of 1 pound meat is $ 4.5 And cost of 1 pound of cheese is $ 2.5.

Step-by-step explanation:

Let the cost of 1 pound of meat be x

Let the cost of 1 pound of cheese be y

Cost of 4 pounds of meat = 4x

Cost of 5 pounds of cheese = 5y

Since we are given that one customer purchases 4 pounds of meat and 5 pounds of cheese for a total of $30.50.  

So, equation becomes :

Cost of 11 pounds of meat = 11x

Cost of 14 pounds of cheese = 14y

Since we are given that a sandwich shop owner comes in and purchases 11 pounds of meat and 14 pounds of cheese for $84.50.

So, equation becomes :

Thus the system of equations are :

-1   (Red line)

-2   (Black line)

Solving these equations graphically we get the solution

x = $4.5

y = $2.5

Hence The cost of 1 pound meat is $ 4.5 And cost of 1 pound of cheese is $ 2.5.

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Answer:

Part B. see the procedure

Part C. see the procedure

Step-by-step explanation:

we have

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g(x)=3-x-x^{2} -----> equation B  

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equate the equation A and the equation B

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The formula to solve a quadratic equation of the form ax^{2} +bx+c=0 is equal to

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in this problem we have

2x^{2}+3x-2=0

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a=2\\b=3\\c=-2

substitute in the formula

x=\frac{-3(+/-)\sqrt{3^{2}-4a(2)(-2)}} {2(2)}

x=\frac{-3(+/-)\sqrt{25}} {4}

x=\frac{-3(+/-)5} {4}

x1=\frac{-3(+)5} {4}=0.5

x2=\frac{-3(-)5} {4}=-2

Find the values of y

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For x=-2

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the solutions are the points

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Part C. Solve the system by graph

using a graphing tool

we know that

The solution of the non linear system is the intersection point both graphs

The intersection points are (0.5,2.25) and (-2,1)

therefore

The solutions are the points (0.5,2.25) and (-2,1)

see the attached figure

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Step-by-step explanation:

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