If the markers are 4.5 inches away on the map, and 2.5 inches represents 10 miles, then we need to make ratios we can work with.
Inches / Miles:
4.5 / x
2.5 / 10
Now, we can cross multiply to end up with:
2.5 * x = 4.5 * 10
Simplify:
2.5x = 45
Divide 2.5 on each side:
2.5x / 2.5 = 45 / 2.5
Simplify:
x = 45 / 2.5
x = 18
Awesome! Now we have a real ratio on the real distance of the markers.
<span>2.5 : 10 & 4.5 : </span><span>18.
</span>
18 miles is the actual distance between the two markers.
Hope I could help! If my math is wrong, or it isn't the answer you are looking for, please let me know!
<span>Have a good one!</span>
5^2 + x^2=8^2
25+x^2=64
X=6.2
3v + 2 = 7v
2 = 4v
1/2 = v
QS = 3v + 2
= 3(1/2)+ 2
= 1.5 + 2
= 3.5
TV = 7v
= 7(1/2)
= 3.5
Only selections B and D give a maximum height of 13 at t=3. However, both of those functions have the height be -5 at t=0, meaning the ball was served from 5 ft below ground. This does not seem like an appropriate model.
We suspect ...
• the "correct" answers are probably B and D
• whoever wrote the problem wasn't paying attention.
Answer:
uh,
Step-by-step explanation:
42-55=7 7+25=32
32:55
i am sorry if this doesn't help!~
