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3 years ago

T(2)=65 and t(14)=305

Mathematics

1 answer:

vazorg [7]3 years ago

5 0

(i) The given AP is 1, 5, 9, 13, 17,...

(i) The given AP is 1, 5, 9, 13, 17,... First term, a = 1 and common difference, d = (5 - 1) = 4

(i) The given AP is 1, 5, 9, 13, 17,... First term, a = 1 and common difference, d = (5 - 1) = 4 T20 = a + (20 - 1)d = a + 19d

(i) The given AP is 1, 5, 9, 13, 17,... First term, a = 1 and common difference, d = (5 - 1) = 4 T20 = a + (20 - 1)d = a + 19d = 1 + 19 ⨯ 4 = 77 

(i) The given AP is 1, 5, 9, 13, 17,... First term, a = 1 and common difference, d = (5 - 1) = 4 T20 = a + (20 - 1)d = a + 19d = 1 + 19 ⨯ 4 = 77 ∴ 20th term = 77

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Option C) 195 characters per minute

Step-by-step explanation:

We are given the following in the question:

Jude types 1,170 characters in 6 minutes..

We have to find the typing rate in characters per minute.

Thus can be done in the following manner:

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3 years ago

Resuelve:

jok3333 [9.3K]

Answer:

A partir del problemas vamos a crear una ecuación donde X es una docena de huevos y Y una libra de mantequilla

entonces: 4 docenas de huevos y 3 libras de mantequilla es igual a 14.100

en mi primera ecuación seria: 4X + 3Y = 14.100

ahora haremos la segunda ecuacion: tres docenas y 1 libra de mantequilla

en mi segunda ecuación seria: 3X + 1Y = 8.700 el plan es sumar las dos ecuaciones pero yo quiero que al sumarlas la variable "Y" desaparezca así que mi segunda ecuación la voy a multiplicar pór (-3) quedándome todo así:

primera ecuación: 4X + 3Y = 14.100

segunda ecuacion multiplicada por -3: -9X - 3Y = -26.1

al sumarlas obtengo como resultado: -5X = -12

resolviendo esa ecuacion obtengo que X=

X=2.4

luego reemplazas X en la primera ecuación: 4X + 3Y = 14.100

reemplazando seria: 4 x (2.4) + 3Y =14.100

9.6 + 3Y = 14.1000

3Y= 14.100 - 9.6

Y=1.5

entonces concluimos que la docena de huevos cuesta 2.4 $ y la libra de mantequilla 1.5 $

Step-by-step explanation:

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3 years ago