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exis [7]
3 years ago
9

What is..Simplify 15.8

Mathematics
1 answer:
ycow [4]3 years ago
5 0

Answer:

simplify of 15.8 is 16

Step-by-step explanation:

please mark me as brainliest

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The Anderson family is preparing for a family reunion. They think they will need 22 juice boxes for every 6 children who attend.
BlackZzzverrR [31]

Answer:

44

Step-by-step explanation:

22 for every six kids

12 is 6 doubled so you double 22 to get 44

8 0
3 years ago
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If f(x) = 3a|4x - 4| - ax, where a is some constant not equal to zero, find f '(1)
dlinn [17]
The slope of an absolute function at the point where it evaluates to zero is undefined.
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3 years ago
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The amount of calories consumed by customers at the Chinese buffet is normally distributed with mean 2885 and standard deviation
aliina [53]

Answer:

a.  X~N(2,885, 651)

b.  0.086291

c.  0.00058

d.  3213.10 calories

Step-by-step explanation:

a. -A normal distribution is expressed in the form X~N(mean, standard deviation).

-Let X a random variable denoting  the number of calories consumed.

-X is a is a normally distributed random variable with mean 2885 and standard deviation 651.

-This distribution is expressed as X~N(2,885, 651)

b. The probability that less than 2000 calories are consumed is calculated using the formula:

P(X

#substitute the given values in the formula to solve for P:

P(X

Hence, the probability of consuming less than 2000 calories is 0.08691

c. The proportion of customers consuming more than 5000 calories is calculated as:

P(X>x)=P(z>\frac{\bar X-\mu}{\sigma})\\\\=P(Z>\frac{5000-2885}{651})\\\\=P(z>3.2488)\\\\=1-0.99942\\\\=0.00058

Hence, the proportion of customers consuming over  5000 calories is 0.00058

d. The least amount of calories to get the award is calculated as:

1% is equivalent to a z value of 0.50399.

-We equate this to the formula to solve for the mean consumption:

0.01=P(z>\frac{\bar X-\mu}{\sigma})\\\\=P(z>\frac{\bar X-2885}{651})\\\\\1\%=0.50399 \\\\\frac{\bar X-2885}{651}=0.50399 \\\\\bar X=0.50399\times 651+2885\\\\=3213.09

Hence, the least amount of calories consumed to qualify for the award is 3213.10 calories.

8 0
3 years ago
I NEED GOOD GRADES PLEASE HELP
Tcecarenko [31]
If my math is right, not even a full day since it’s 2 2/3 and they use 8
6 0
3 years ago
Round 124,607 to the nearest hundred thousand
ANEK [815]
The answer is 100,000
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