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3 years ago

What is the equation of this graphed line?

Mathematics

2 answers:

JulijaS [17]3 years ago

7 0

Answe

2, 1 Step-by-step explanation:

koban [17]3 years ago

6 0

Answer:

Haven't done this in a minute but I think it's (2,1)

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Find the inverse of this matrix. 1 -1 -1 -1 2 3 1 1 4

zheka24 [161]

Let's use Gaussian elimination. Consider the augmented matrix,

$\left[\begin{array}{ccc|ccc}1 & -1 & -1 & 1 & 0 & 0\\-1 & 2 & 3 & 0 & 1 & 0\\1 & 1 & 4 & 0 & 0 & 1\end{array}\right]$

• Add row 1 to row 2, and add -1 (row 1) to row 3:

$\left[\begin{array}{ccc|ccc}1 & -1 & -1 & 1 & 0 & 0\\0 & 1 & 2 & 1 & 1 & 0\\0 & 2 & 5 & -1 & 0 & 1\end{array}\right]$

• Add -2 (row 2) to row 3:

$\left[\begin{array}{ccc|ccc}1 & -1 & -1 & 1 & 0 & 0\\0 & 1 & 2 & 1 & 1 & 0\\0 & 0 & 1 & -3 & -2 & 1\end{array}\right]$

• Add -2 (row 3) to row 2:

$\left[\begin{array}{ccc|ccc}1 & -1 & -1 & 1 & 0 & 0\\0 & 1 & 0 & 7 & 5 & -2\\0 & 0 & 1 & -3 & -2 & 1\end{array}\right]$

• Add row 2 and row 3 to row 1:

$\left[\begin{array}{ccc|ccc}1 & 0 & 0 & 5 & 3 & -1\\0 & 1 & 0 & 7 & 5 & -2\\0 & 0 & 1 & -3 & -2 & 1\end{array}\right]$

So the inverse is

$\begin{bmatrix}1&-1&-1\\-1&2&3\\1&1&4\end{bmatrix}^{-1} = \boxed{\begin{bmatrix}5&3&-1\\7&5&-2\\-3&-2&1\end{bmatrix}}$

3 0

3 years ago

The book if it has 275 pages?

Troyanec [42]

hopefully the attached images help you,

Zara♡

6 0

2 years ago

Read 2 more answers

2 questions what is bigger 0.247 or 323/600 and does anyone wanna be my friend?

Rufina [12.5K]

Answer:

Step-by-step explanation: 1.

323 divided by 600 will be 0.5833333333...

0.583333333... is greater than 0.247

2. Ok I’ll be ur friend!

5 0

3 years ago

Read 2 more answers

Translate the sentence into an equation.

deff fn [24]

Answer:

3(b+7)=6

Sum means adding, so 3 is multiplied by (b+7)

4 0

3 years ago

41. What is the image of O(- 3, - 2) after two reflections, first across the line y = - 5 , then across the line x = 1 ? (1 poin

liberstina [14]

Answer:

D(5,-8)

Step-by-step explanation:

The given point is (-3,-2)

When we reflect in the line y=k, we use the rule (x, 2k-y)

This implies that:

$(-3, - 2)\to (-3, 2*-5--2)$

$(-3, - 2)\to (-3, - 8)$

When we reflect in the line x=k, we use the rule

$(x,y)\to (2k-x,y)$

Now we have x=1

This implies that:

$( - 3, - 8)\to (2 \times 1- - 3, - 8)$

$( - 3, - 8)\to (5, - 8)$

4 0

4 years ago