Answer:
The expected value of the winnings for a single-ticket purchase is -$1.0016.
Step-by-step explanation:
The total number of tickets sold is, <em>N</em> = 1250.
Cost of one ticket is, $4.
Let <em>X</em> = amount of prize.
The prize distribution is as follows:
1 Grand price = $3000
1 Second prize = $450
10 Third prize = $25
The expected value <em>X</em> can be computed using the formula:
Compute the probability distribution of <em>X</em> as follows:
Prize Amount (X) P (X) x · P (X)
1 Grand prize $3000 
1 Second prize $450 
10 Third prize $25 
No prize -$4 
TOTAL 1.0000 -1.0016
Thus, the expected value of the winnings for a single-ticket purchase is -$1.0016.
Answer:
upward?
Step-by-step explanation:
Answer:
The correct options are;
Therefore, City A is likely to have temperatures that remain fairly constant all year round because it has a compact interquartile range compared to that of City B
City B is likely to have more extreme temperatures with colder days in the winter and hotter days in the summer because the range is greater than that of A
Step-by-step explanation:
Here we have for City A
Maximum - Minimum = 10
Interquartile range =3
City B
Maximum - Minimum = 18.5
Interquartile range =9.5
Therefore, City A is likely to have temperatures that remain fairly constant all year round because it has a compact interquartile range compared to that of City B
City B is likely to have more extreme temperatures with colder days in the winter and hotter days in the summer because the range is greater than that of A.
