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3 years ago

Math Question for An assignment

Mathematics

1 answer:

muminat3 years ago

8 0

Answer: y = 5/2x + 4

Step-by-step explanation:

y = 5/2x + c

1) Substitute

-6 = 5/2(-4) + c

-6 = -10 + c

-6 + 10 = c

4 = c

y = 5/2x + 4 or

y = 2.5x + 4

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Mazyrski [523]

Answer:

The Answer Is C

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3 years ago

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Find the area of quadrilateral ABCD. A. 27.28 units² B. 33.08 units² C. 28.53 units² D. 26.47 units²

Ludmilka [50]

Answer:

<h3> $\boxed{ \boxed{ \bold{ \purple{ \sf{28.53 \: {units}^{2} }}}}}$ </h3>

Option C is the correct option.

Step-by-step explanation:

For ABD

$\sf{ = \frac{2.89 + 8.59 + 8.6}{2} }$

$\sf{ = \frac{20.08}{2} }$

$\sf{ = 10.04}$

∆ ABD = $\sf{ = \sqrt{10.04(10.04 - 2.89)(10.04 - 8.59)(10.04 - 8.6)} }$

$\sf{ = \sqrt{10.04 \times 7.15 \times 1.45 \times 1.44 }}$

$\sf{ = \sqrt{149.8891} }$

$\sf{ = 12.2429}$

For ∆ ACD ,

$\sf{s = \frac{8.6 + 4.3 + 7.58}{2} }$

$\sf{ = \frac{20.48}{2} }$

$\sf{ = 10.24}$

∆ ACD = $\sf{ = \sqrt{10.24(10.24 - 8.6)(10.24 - 4.3)(10.24 - 7.58} }$

$\sf{ \sqrt{10.24 \times 1.64 \times 5.94 \times 2.66} }$

$\sf{ = \sqrt{265.3456} }$

$\sf{ = 16.2894}$

Area of quadrilateral ABCD = $\sf{12.2429 + 16.2894}$

$\sf{ = 28.5323}$

$\sf{ = 28.53}$ units ²

Hope I helped!

Best regards!

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3 years ago

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Sholpan [36]

Answer:

The first five terms of the arithmetic sequence.

-10 , -8 , -6 , -4 ,-2 ..........

Step-by-step explanation:

<u><em>Explanation</em></u>

Given that the first term is -10 and common difference d = 2

we know that the sequence in A.P

a ,a+d ,a+2d,a+3d ,a+4d........... are in AP

-10, -10+2, -10+2(2), -10+3(2) , -10+4(2)..................

-10 , -8 , -6 , -4 ,-2 ..........

<u><em>Final answer:-</em></u>

The first five terms of the arithmetic sequence.

-10 , -8 , -6 , -4 ,-2 ..........

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Answer:

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According to the question,

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