Determine the equation of the circle graphed below.

olga_2 [115]

.25 Is the answer If that helps you enough

3 0

3 years ago

Two common names for streets are FirstFirst Street and MainMain â€‹Street, with 14 comma 86614,866 streets bearing one of these

oksian1 [2.3K]

Answer: There are 7,677 streets named as " First Street" and 7, 189 streets named as "Main Street" .

Step-by-step explanation:

Let x be the number of streets named as First Street .

y be the number of streets named as Main Street.

AS per the given information, we have the following system of equations :

$x+y=14866-------------(1)\\\\x=488+y-------------(2)$

Substitute the value of x from (2) in (1) , we get

$488+y+y=14866\\\\ 2y =14866- 488\\\\ 2y=14378\\\\ y=7189$

Put value of y in (2), we get

$x=488+7189=7677$

Hence , there are 7,677 streets named as " First Street" and 7, 189 streets named as "Main Street" .

6 0

2 years ago

What is the fourth term in the binomial expansion (a+b)^6)

Dafna11 [192]

Answer:

$20a^3b^3$

Step-by-step explanation:

<u>Binomial Series</u>

$(a+b)^n=a^n+\dfrac{n!}{1!(n-1)!}a^{n-1}b+\dfrac{n!}{2!(n-2)!}a^{n-2}b^2+...+\dfrac{n!}{r!(n-r)!}a^{n-r}b^r+...+b^n$

<u>Factorial</u> is denoted by an exclamation mark "!" placed after the number. It means to multiply all whole numbers from the given number down to 1.

Example: 4! = 4 × 3 × 2 × 1

Therefore, the fourth term in the binomial expansion (a + b)⁶ is:

$\implies \dfrac{n!}{3!(n-3)!}a^{n-3}b^3$

$\implies \dfrac{6!}{3!(6-3)!}a^{6-3}b^3$

$\implies \dfrac{6!}{3!3!}a^{3}b^3$

$\implies \left(\dfrac{6 \times 5 \times 4 \times \diagup\!\!\!\!3 \times \diagup\!\!\!\!2 \times \diagup\!\!\!\!1}{3 \times 2 \times 1 \times \diagup\!\!\!\!3 \times \diagup\!\!\!\!2 \times \diagup\!\!\!\!1}\right)a^{3}b^3$