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2 years ago

Select all input values for which f(x) = 3.

Mathematics

1 answer:

schepotkina [342]2 years ago

8 0

I have this to bro I’m looking for the answer key

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Which point on the number line is at 58/100

liberstina [14]

Answer:

Step-by-step explanation:

if you look at it 0 is the first one then count up by tens Q would 48 because it’s before 50 so 50 is right next to Q so then R is before 60 and after 50 so R is 58/100

8 0

2 years ago

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What is 0.29 of 200 rounded to the nearest hundred

jekas [21]

Answer:

$100$

Step-by-step explanation:

Step 1: Make an expression

$200 * 0.29 = x$

$58 = x$

Step 2: Round

$58$

$100$

Answer: $100$

3 0

2 years ago

Probability of impossible event is ………… [. ] a) 0 b) 100% c) 1 d) both b & C

Andre45 [30]

Answer:

Step-by-step explanation:

7 0

2 years ago

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Tom sells baseball cards at 10 for 35 cents. Is that a better deal than 12 for 40 cents?

AVprozaik [17]

For either one of the deals, just find what one card equals and times it by how many cards the other equation has.

e.g. 0.35 cents divide by 10 = 0.035. And now, you times it by 12 since the other deal is 12 cards for 40 cents.

0.035 x 12 = 0.48

So, 10 cards for 35 cents is not the better deal.

7 0

3 years ago

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Given the circle with the equation (x + 1)2 + y2 = 36, determine the location of each point with respect to the graph of the cir

kati45 [8]

$\bf \textit{equation of a circle}\\\\ 
(x- h)^2+(y- k)^2= r^2
\qquad 
center~~(\stackrel{}{ h},\stackrel{}{ k})\qquad \qquad 
radius=\stackrel{}{ r}\\\\
-------------------------------\\\\
(x+1)^2+y^2=36\implies [x-(\stackrel{h}{-1})]^2+[y-\stackrel{k}{0}]^2=\stackrel{r}{6^2}~~~~
\begin{cases}
\stackrel{center}{(-1,0)}\\
\stackrel{radius}{6}
\end{cases}$

so, that's the equation of the circle, and that's its center, any point "ON" the circle, namely on its circumference, will have a distance to the center of 6 units, since that's the radius.

$\bf ~~~~~~~~~~~~\textit{distance between 2 points}
\\\\
(\stackrel{x_1}{-1}~,~\stackrel{y_1}{0})\qquad 
A(\stackrel{x_2}{-1}~,~\stackrel{y_2}{1})\qquad \qquad 
% distance value
d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}
\\\\\\
\stackrel{distance}{d}=\sqrt{[-1-(-1)]^2+(1-0)^2}\implies d=\sqrt{(-1+1)^2+1^2}
\\\\\\
d=\sqrt{0+1}\implies d=1$

well, the distance from the center to A is 1, namely is "inside the circle".

$\bf ~~~~~~~~~~~~\textit{distance between 2 points}
\\\\
(\stackrel{x_1}{-1}~,~\stackrel{y_1}{0})\qquad 
B(\stackrel{x_2}{-1}~,~\stackrel{y_2}{6})\\\\\\
\stackrel{distance}{d}=\sqrt{[-1-(-1)]^2+(6-0)^2}\implies d=\sqrt{(-1+1)^2+6^2}
\\\\\\
d=\sqrt{0+36}\implies d=6$

notice, the distance to B is exactly 6, and you know what that means.

$\bf ~~~~~~~~~~~~\textit{distance between 2 points}
\\\\
(\stackrel{x_1}{-1}~,~\stackrel{y_1}{0})\qquad 
C(\stackrel{x_2}{4}~,~\stackrel{y_2}{-8})
\\\\\\
\stackrel{distance}{d}=\sqrt{[4-(-1)]^2+[-8-0]^2}\implies d=\sqrt{(4+1)^2+(-8)^2}
\\\\\\
d=\sqrt{25+64}\implies d=\sqrt{89}\implies d\approx 9.43398$

notice, C is farther than the radius 6, meaning is outside the circle, hiking about on the plane.

3 0

2 years ago

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