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nikitadnepr [17]
2 years ago
12

A 28.5 g piece of gold is heated and then allowed to cool. What is the change in temperature (°C) if the gold releases 0.106 kJ

of heat as it cools? The molar heat capacity of gold is 25.4 J/mol・°C.
Chemistry
1 answer:
Shkiper50 [21]2 years ago
4 0

Considering the definition of calorimetry and sensible heat, the change in temperature if the gold releases 0.106 kJ of heat as it cools is 28.78°C.

Calorimetry is the measurement and calculation of the amounts of heat exchanged by a body or a system.

Sensible heat is the amount of heat that a body absorbs or releases without any changes in its physical state (phase change). It is calculated by the expression:

Q = c× m× ΔT

where Q is the heat exchanged by a body of mass m, made up of a specific heat substance c and where ΔT is the temperature variation.

In this case, you know:

  • Q= 0.106 kJ= 106 J (being 1 kJ=1000 J)
  • c= 25.4 \frac{J}{molC}
  • m= 28.5 g×\frac{1 mole}{196.967 g} = 0.145 moles (being 196.967 g/mole the molar mass of gold)
  • ΔT= ?

Replacing:

106 J= 25.4 \frac{J}{molC}× 0.145 moles× ΔT

Solving:

ΔT=\frac{106 J}{25.4\frac{J}{molC}x0.145 moles}

ΔT= 28.78 C

The change in temperature if the gold releases 0.106 kJ of heat as it cools is 28.78°C.

Learn more:

  • brainly.com/question/11586486?referrer=searchResults
  • brainly.com/question/24724338?referrer=searchResults
  • brainly.com/question/7435791
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A sample of quartz is put into a calorimeter (see sketch at right) that contains of water. The quartz sample starts off at and t
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Answer:

0.71 J/g°C

Explanation:

Here is the complete question

thermometer A 51.9 g sample of quartz is put into a calorimeter (see sketch at right) that contains 300.0 g of water. The quartz sample starts off at 97.8 °C and the temperature of the water starts off at 17.0 °C. When the temperature of the water stops changing it's 19.3 °C. The pressure remains constant at 1 atm. insulated container water sample Calculate the specific heat capacity of quartz according to this experiment. Be sure your answer is rounded to 2 significant digits. a calorimeter g °C

Solution

Since the temperature of the water increases from 17.0 °C to 19.3 °C, it means that it loses heat. Also, the final temperature of the quartz equals the final temperature of the water 19.3 °C. Since the quartz temperature decreases from 97.8 °C to 19.3 °C it loses heat.

So, heat lost by quartz, Q = heat gained by water, Q'

-Q = Q'

-mc(θ₂ - θ₁) = m'c'(θ₂ - θ₃) where m = mass of quartz = 51.9 g, c = specific heat capacity of quartz, θ₁ = initial temperature of quartz = 97.8 °C, θ₂ = final temperature of quartz = 19.3 °C, m' = mass of water = 300 g, c = specific heat capacity of water = 4.2 J/g °C , θ₃ = initial temperature of water = 17.0 °C, θ₂ = final temperature of water = 19.3 °C

Making c subject of the formula, we have

c = -m'c'(θ₂ - θ₃)/m(θ₂ - θ₁)

Substituting the values of the variables into the equation, we have

c = -300 g × 4.2 J/g °C(19.3 °C - 17.0 °C)/51.9 g(19.3 °C - 97.8 °C)

c = -1260 J/°C(2.3 °C)/51.9 g(-78.5 °C)

c = -2898 J/-4074.15 g°C

c = 0.711 J/g°C

c ≅ 0.71 J/g°C to 2 significant digits

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