Question

Carbon dioxide gas occupies a volume of 20.0 L at 308K and 2.30 atm. What volume would it occupy at 416 K and 5.40 atm?

Answer 1

Answer : The final volume of gas is, 11.5 L

Explanation :

Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is,

$\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}$

where,

$P_1$ = initial pressure of gas = 2.30 atm

$P_2$ = final pressure of gas = 5.40 atm

$V_1$ = initial volume of gas = 20.0 L

$V_2$ = final volume of gas = ?

$T_1$ = initial temperature of gas = 308 K

$T_2$ = final temperature of gas = 416 K

Now put all the given values in the above equation, we get:

$\frac{2.30atm\times 20.0L}{308K}=\frac{5.40atm\times V_2}{416K}$

$V_2=11.5L$

Therefore, the final volume of gas is, 11.5 L

Answer 2

Answer:

The new volume is 11.5 L

Explanation:

Step 1: Data given

Volume of carbon dioxide gas = 20.0 L

Initial temperature = 308 K

Initial pressure = 2.30 atm

The temperature changes to 416 K

The pressure changes to 5.40 atm

Step 2: Calculate the new volume

(P1*V1)/T1 = (P2*V2)/T2

⇒ with P1 = the initial pressure = 2.30 atm

⇒ with V1 = the initial volume = 20.0 L

⇒ with T1 = the initial temperature = 308 K

⇒ with P2 = the final pressure = 5.40 atm

⇒ with V2 = the final volume = TO BE DETERMINED

⇒ with T2 = the final temperature = 416 K

(2.30*20.0)/308 = (5.40*V2) / 416

V2 = 11.5 L

The new volume is 11.5 L