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attashe74 [19]
3 years ago
6

Write the 5 major characteristics of traditional map making ​

Chemistry
1 answer:
ratelena [41]3 years ago
3 0

Answer:

insta

Explanation:

Zak_1231 follow me

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Carbohydrates are found in ..... Question 5 options: water alcohols plastics starchy sugar-filled foods mutil choice
nirvana33 [79]

starchy sugar filled foods contain carbohydrates since carbohydrates are sugar chains

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3 years ago
Name the two subatomic particles found in the nucleus.
Vesna [10]

i can think of 3 subatomic particles found in a nucleus protons, neutrons, and electrons

6 0
3 years ago
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The ions Cr3+ and O2- combine to form the ionic compound chromium oxide. In what proportions do these ions combine to produce a
Anit [1.1K]
To find the ratio of the the combination for the ion, write the charge of the cation as the subscript for the anion, and the charge of the anion as the subscript of the cation. This will make the charges effectively cancel and you will be left with a neutral ionic compound. Remember, that an ionic compound is made up of a metal and a nonmetal.
For Cr3+ and O2-, you will get the neutral compound to be Cr₂O₃.

The proportion these ions combine in is 2 to 3. 2 ions of Cr3+ and 3 ions of O2-

Your answer is D) 2:3
6 0
4 years ago
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How many molecules of hydrogen gas will be produced when 0.2moles of aluminium react completely according to the following equat
Angelina_Jolie [31]

Answer:

8

Explanation:

5 0
4 years ago
The half-life of carbon-14 is 5730 years. How many grams of carbon-14 remain after 28,650 years if the original amount was 28.0
alexdok [17]
TLDR: the answer is C. 0.875.

The basis of this problem is testing your fluency with half-life radioactive decay. The half-life of any radioactive substance represents the amount of time required for 1/2 of the amount of the substance to decay. So, if you had a 100 g sample of Carbon-14, after 5,730 years, only 50 g of Carbon-14 would remain; the other 50 g of substance would have decayed into another substance (Nitrogen-14). If another 5,730 years passes, only 25 g would remain, as half of that 50 g radioactive substance would have decayed.

In the problem, 28 g of Carbon-14 decays as 28,650 years passes, which, when divided by 5,730, yields a value of 5. This number represents the number of half lives that passes during this time. So, over the course of this time, the amount of radioactive substance is cut in half five times.

28 g - 14 g (1 HL) - 7 g (2 HL) - 3.5 (3 HL) - 1.75 g (4 HL) - 0.875 g (5 HL)

After 5 half lives, only 0.875 g of the original 28 g remains.
5 0
3 years ago
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